Q19 and Q20 Q19-Derive an expression for true strain as a function of D and Do for a tensile testspecimen of round cross-section.Q20-The following data are collected during a tensile test in which the starting gagelength = 125.0 mm and the cross- sectional area = 62.5 mm2:23,042131.25Load (N)27,578153.0017,79327,579140.0528,91320,4620 125.23Length (mm)The maximum load is 28,913 N and the final data point occurred immediately prior tofailure.(a)Plot the engineering stress strain curve. Determine: (b) yield strength Y,(c) modulus of elasticity E,(d) tensile strength UTS (e). determine the strength coefficient and the strainhardening exponent. Be sure not to use data after the point at which necking147.01160.10occurred...Ans b-Y = 310.27 MPa , c- e=168,625 MPa. d.UTS=426.6 MPa e- n = 0.283,K = 910.2 MPa0.283The flow curve equation is: o = 910.2 e

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Q19-Derive an expression for true strain as a function of D and Do for a tensile test specimen of round cross-section.

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Concept explainers

Stress transformation

The term stress indicates the measure of internal forces that develop due to an external force's application on an object. When a specific external force is applied to an object, internal stress generates in the material. The value of stress can obtain by taking the ratio of the externally applied force and cross-sectional area of the object. There are different types of stress depending on the type of external force.

Question

Q19 and Q20

Q19-Derive an expression for true strain as a function of D and Do for a tensile test
specimen of round cross-section.
Q20-The following data are collected during a tensile test in which the starting gage
length = 125.0 mm and the cross- sectional area = 62.5 mm2:
23,042
131.25
Load (N)
27,578
153.00
17,793
27,579
140.05
28,913
20,462
0 125.23
Length (mm)
The maximum load is 28,913 N and the final data point occurred immediately prior to
failure.(a)Plot the engineering stress strain curve. Determine: (b) yield strength Y,
(c) modulus of elasticity E,
(d) tensile strength UTS (e). determine the strength coefficient and the strain
hardening exponent. Be sure not to use data after the point at which necking
147.01
160.10
occurred...
Ans b-Y = 310.27 MPa , c- e=168,625 MPa. d.UTS=426.6 MPa e- n = 0.283,
K = 910.2 MPa
0.283
The flow curve equation is: o = 910.2 e

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