2/7 The two structural members, one of which is in ten-sion and the other in compression, exert the indicatedforces on joint O. Determine the magnitude of the re-sultant R of the two forces and the anglemakes with the positive x-axis.which RAns. R = 3.61 kN, 0 = 206°2 kN30°100/1000[Pep/p0p]||wwwwwwwwwwwProblem 2/73 kN60°x

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Answered: 2/7 The two structural members, one of…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Problem 3. What is the moment of the 1.4 kN force along the direction of the 1.0 kN force? Express your answer as a magnitude and sketch the direction of rotation about the axis defined by the 1.0 kN force TIGBAO TK 1.0KN X 539 indi 21 150 mm 195 mm 2 4 160 mm 21% ARD 19TO 1.4 kN MEBIRT 0 DAW ITOM 00 1400
URGENT sir
Answer for the 1st part of the problem. magnitude of force A = 74 N direction of force A = 25o north of west second force = P direction of force P = α south of west arrow_forward The resultant of two forces is horizontal , it means that the y component of resultant = 0 Ry = ASin(25o) - PSin(α) 0 = (74×0.42) - PSin(α) PSin(α) = 31.08 NFor, the smallest force P , the value of Sinα must be maximum which is 1 when the value of αis 90 degree Thus, P×Sin(90o) = 31.08 N P = 31.08 N The magnitude of smallest force P = 31.08 N the direction of force P = 90 degree south of west = along - y axis= arrow pointing vertically downw
Problem 5 Determine the magnitudes of the components of the force acting along the axis AB of the wrench handle and perpendicular to it. Son Can toa 300 mm x B 9 = 128° (0,0,300) 500 mm UF = COS 30%. Sin us i = -0.6124; + 0.6124j F = 80 N 30 5 45" + Cos 30° cos 45j+ sin 30 + 0.5k (0,500, 300) UAB = -j Cos 0 = UF • UAB = (-.61241 - 0.61245 +95 k) (-j) I How do we go from this = -0.6124 to this?
touchO 0"| 63% ( 23:50 MENG250 - Practice Assi... Not saved yet Page Break *2-60. Determine the magnitude and coordinate direction angles of the resultant force acting on the bracket. F1 = 450 N 45° 30° 60° F2 = 600 N O
If the component of a force along x-axis is Fx = 20 kN and along y-axis is Fy = 30 kN, and if “t” is an axis making an angle of 30o in the clockwise direction with respect to x-axis, what would be the components of this force Ft and Fn along the orthogonal axes “t” and “n”, respectively? Select one: Ft = 32.32 kN and Fn =15.98 kN Ft = 2.32 kN and Fn = 35.98 kN Ft = 15.98 kN and Fn = 32.2 kN Ft = 35.98 kN and Fn = 2.32 kN
S00 Ib In the fig. shown, compute the ff: (16-18) the resultant using cosine law (force polygon) 60 R = 35 (19-20) the angle of the R measured 500 lb cW from the x- axis.
Please help me answer this correctly ASAP. Please write the solution on paper. Thank you. Note: The tolerance is ± 1 in the third significant digit.
If the component of a force along x-axis is Fx = 20 kN and along y-axis is Fy = 30 kN, and if “t” is an axis making an angle of 30o in the counter clockwise direction with respect to x-axis, what would be the components of this force Ft and Fn along the orthogonal axes “t” and “n”, respectively? Select one: Ft = 2.32 kN and Fn = 35.98 kN Ft = 15.98 kN and Fn = 32.32 kN Ft = 35.98 kN and Fn = 2.32 kN Ft = 32.32 kN and Fn =15.98 kN
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Assign the values of shear force and bending moment to the image bar as a function of the x coordinate. q=20kN/m F=14kN M=12kNm L1=1.2m L2=1.4m L3=1.3m L4=1.5m Minimum value of shear force: Qmin = Maximum value of shear force: Qmax= Use units (kN,m), Do not round the invoices in the intermediate stages, but only the final answer!

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