Q1. The work done on an object is equal to the integral of the force on that object dotted with its displacent. This looks like W=J(F.ds) (W is work, Fis force, and ds is the infinitesimally small displacement vector). For a force whose direction is the line of motion, the equation becomes W=J (Fdx). If the force on an object as a function of displacement is F(x)=3x²+x, what is the work as a function of displacement (using calculus application) W(x)? Assume W(0)=0 and the force is in the direction of the object's motion.

College Physics
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ISBN:9781305952300
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Chapter1: Units, Trigonometry. And Vectors
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Q1. The work done on an object is equal to the integral of the force on that object dotted with
its displacent.
This looks like W=J(F.ds) (W is work, Fis force, and ds is the infinitesimally small displacement
vector). For a force whose direction is the line of motion, the equation becomes W=J (Fdx).
If the force on an object as a function of displacement is F(x)3D3x²+x, what is the work as a
function of displacement (using calculus application) W(x)? Assume W(0)=0 and the force is in
the direction of the object's motion.
Transcribed Image Text:Q1. The work done on an object is equal to the integral of the force on that object dotted with its displacent. This looks like W=J(F.ds) (W is work, Fis force, and ds is the infinitesimally small displacement vector). For a force whose direction is the line of motion, the equation becomes W=J (Fdx). If the force on an object as a function of displacement is F(x)3D3x²+x, what is the work as a function of displacement (using calculus application) W(x)? Assume W(0)=0 and the force is in the direction of the object's motion.
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