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- Compare the IR carbonyl stretching frequencies of the following compounds to that of acetone. Compare the table as follows: (a) State whether the carbonyl stretching frequency is higher, lower, or about the same as acetone (b) State the dominant effect responsible for the change in frequency relative to acetone (i.e., resonance, inductive, mass change, none) (c) Rank the compounds with numbers 1 through 4 in order of carbonyl stretching frequency from highest to lowest (1 = highest; 4 = lowest) H3C CH3 HN acetone v = 1715 cm-1 |(i) higher/lower/same v than acetone (ii) indicate the dominant effect (iii) rank the compounds from highest (1) to lowest (4) in stretching vCalculate the degrees of unsaturation from the molecular formulae provided below. Hint: for S, think about where it is in relationship to other atoms on the periodic table how many bonds can it make?(plz give detail explanation )
- Identify how IR spectroscopy might be used to monitor the progress of the following reaction. [conc. H,SO,]Use the HNMR spectra shown here to determine the structural formula for the unknown cited below. Begin by calculating the degree of unsaturation for the compound. This will help you determine the total number of pi bonds plus rings that are possible for the structure. The table of chemical shift values are provided.I need the answer as soon as possible
- Show why the wavenumber frequency for D2 for the symmetric stretch is 2990 cm-1, whereas that of H2 is 4401 cm-1? What does that tell you about the bond strength of H2 relative to that of D2? Hint: D is a heavier isotope of HydrogenAttempt to rank the following compounds in order of decreasing carbonyl stretching frequency. In other * Please esplein whyPredict whether the compound is aromatic , anti-aromatic from a list of cyclic molecules given below and explain why? Also circle all the basic nitrogen’s?
- Proton Hc is the most and the most (, with a chemical shift of approximately. The carboxylic acid proton,, will be the most | and the furthest . The chemical shift of is approximately 11 ppm. Protons on benzene rings usually have a chemical shift of. Electron withdrawing groups cause because the electron density around the nucleus is resulting in a ( chemical shift. На H. H2N. HO H Н. H, deshielded shielded upfield downfield 2.5 ppm 1.0 ppm 7-9 ppm На Не НЬ shielding deshielding decreased increased smaller largerRank the following compounds from shortest absorption wavelength to longest absorption wavelength. a b Shortest LongestThe following H-NMR spectrum (showing all available signals) is for one of the possible products listed below. This product was obtained from oxidizing one of the alcohols listed below (as possible reactants) using either dichromate (Na2Cr2O7/H2SO4) or DMP. Determine the product, reactant and oxidizing agent following the analysis below. Based on the given H-NMR spectrum, and since there is signals is and the total number of H-NMR the oxidation product must be ÷ Therefore, the oxidizing agent and the reactant must be PPM Possible Reactants OH A Possible Products O I V ОН B ОН VI II ОН C ОН OH III VII OH D OH E IV VIII