Q1) the results of a standard compaction test are : w% 6.2 8.1 9.8 11.5 12.3 13.2 Ywet(KN/m³) | 16.9 Find 1- the max. dry density and OMP , 2- plot the zero void line. 18.7 19.5 20.5 20.4 20.1 ( Note ;the specific gravity of soil is 2.7).

Q1) the results of a standard compaction test are : w% 6.2 8.1 9.8 11.5 12.3 13.2 Ywet(KN/m³) | 16.9 Find 1- the max. dry density and OMP , 2- plot the zero void line. 18.7 19.5 20.5 20.4 20.1 ( Note ;the specific gravity of soil is 2.7).

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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The results of a standard compaction test for a soil having a value of (Gs = 2. 5) are shown in the table below. Water 6.2 8.1 9.8 11.5 12.3 13.2 Content (%) Unit Weight | (KN/m³) 16.9 18.7 19.5 20.5 20.4 20.1 Determine: i) The optimum moisture content (OMC) and the maximum dry unit weight (MDW).
From a standard Proctor laboratory sample of soil Gs= 2.70; maximum dry unit weight = 16.4 kN/m3; Optimum moisture content= 18%; Moisture content of soil at the borrow site+ 28%. Specification require that compaction of soil must be at least 95% of the maximum obtained from the proctor test. Compute the maximum compaction expected from the compacted soil using the zero air boids curve for this soil with the following moisture contents: w1= 20%; w2= 25%; w3= 30%.
The laboratory compaction test of a certain type of soil gives a maximum dry density of 1.486 g/cm3 with an optimum moisture content of 12.5%. The following are the results of a field unit weight determination test using sand cone method. Volume of the soil excavated from the hole = 0.001337 m3 Weight of soil from the hole when wet = 2220 g Weight of soil when dry = 1890 g What is the in situ water content of the soil? O 17.46% O 19.21% O 15.55% O 14.12%
From a standard Proctor laboratory sample of soil Gs= 2.70; maximum dry unit weight = 16.4 kN/m3; Optimum moisture content= 18%; Moisture content of soil at the borrow site+ 28%. Specification require that compaction of soil must be at least 95% of the maximum obtained from the proctor test. Compute the maximum compaction expected from the compacted soil using the zero air boids curve for this soil with the following moisture contents: w1= 20%; w2= 25%; w3= 30%. O a. 94.71% O b. 96.54% O c. 92.07% O d. 90.12%
Sand is used in the cone is known to have a bulk density of 15.74 kN/m3 Wet weight=20.601 N Dry weight =17.926 N Weight of sand to fill test hole =16.053 N a) Determine the in-place dry density of the tested soil (Ans. 17.57 kN/m3) b) Determine the water content (Ans. 15%) c) Compute the percentage of compaction of the tested soil if the laboratory moisture density curve indicates a dry density of 18.1 kN/m3 and an optimum moisture content of 13%. (Ans. 97.07%)
Bulk Unit Weight (kN/m3) 20.0 20.7 21.7 21.4 21.1 Water Content (%) 8.0 9.5 11.5 12.5 13.5 1. Determine dry unit weight and water content at 95% standard compaction based on the result of a standard compaction test given 2. Describe effect of water content during compaction between 9.5% water content to 12.5% water content
3. Problem 3. Sand sample has the relative density D, = 0.65, emax = 0.75; e min = 0.52, G₁ = 2.67. Find the void ratio e and the dry unit weight ye (the unit is up to you)
The laboratory compaction test of a certain type of soil gives a max dry density of 1.486 gm/cu.cm with an optimum water content of 12.5%. The ff are the results of a field density test using sand code equipment: Volume of soil excavated from the hole= 0.001337 cu.m. Weight of wet soil from the hole- 2220 grams Weight of soil after oven drying= 1890 grams a. Determine the field unit weight of the soil in gm/cu.cm. b. Find the water content of soil. c. What is the relative compaction?
A compacted fill of 3.0 m height is to be placed over a large area. The soil profile under the area is shown in the scheme below. An oedometer test on a sample from point A produced the following results: Ce C, eo o(kPa) Sample A: 0.40 0.08 1.10 70.0 These results can be used in settlement calculations for the soft clay stratum as a whole. Compute the total settlement below centre of the area due to the weight of the fill.
the modified compaction method for the same soil sample gives 10 points . .moisture value than the standard compaction method and ..2. max. dry density value 1 (lower) 2(lower) O 1 (lower) 2(greater) O 1(greater) 2(lower) O 1(greater) 2(greater)
PROBLEM 13: A soil sample has a maximum dry unit weight of 125 Ib/ft?. If the sample has wet unit weight of 135 Ib/ft?, Gs =2.65, moisture content w =11%. Compute the percent compaction in the field a. 97.3% C. 89.67% b. 94.13% d. 93.23%
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