For a given sandy soil, emax = 0.91, emin = 0.48, Gs = 2.67, w = 9%, relative density is 78%. Determine the void ratio. Determine the unit weight of compaction in the field.

Q: Q1) the results of a standard compaction test are : w% 6.2 8.1 9.8 11.5 12.3 13.2 Ywet(KN/m³) | 16.9…

A: Given above table we have to find the 1- maximum dry density and OMP 2- plot zero void line

Q: A soil deposit has a void ratio of 0.9. Its void ratio is reduced to 0.6 by compaction. Determine…

A:

Q: Answer 4.3

A:

Q: A cohesive soil yields a maximum dry density of 16 kN/m³ during a standard Proctor Compaction test.…

A:

Q: A cohesive soil yields a maximum dry density of 18kN/m³3 during a standard proctor compaction test.…

A:

Q: determine the density index of a soil having a natural void ratio 0.7. The void ratio of the soil in…

A: Given: Natural void ratio of soil, e = 0.7 Void ratio of soil in loosest state, emax = 0.85 Void…

Q: Given data Degree of saturation=D0.5 Void ratio=0:47 Specific gravity of soil=2.7 Determine water…

A:

Q: 18. Problems Problem 4.1 The maximum and minimum dry unit weights of a sand were determined in the…

A:

Q: Problem 1. A proctor test is performed on a sandy soil. The unit weights and water contents…

A: Detailed solution is attached below as

Q: The ff are results of a field unit weight determination test Volume hole 0.0016 Mass of moist soil…

A:

Q: Problem 7: A 3-m high sandy fill material was placed loosely at a relative density of 55%.…

A: Height of sandy fill (H) = 3m Relative Density before compaction (RD1) = 55% Relative Density after…

Q: For a given sandy soil, emax= 0.75, emin= 0.46 and Gs= 2.68. What is the unit weight of compaction…

A:

Q: For a sandy soil, emax = 0.72, emin = 0.46, and G, = 2.68. What is the moist unit weight of…

A: We have relationRelative density Dr=emax-eemax-emin10078%=0.72-e0.72-0.46×100e=0.71797

Q: Q.1 What is the void ratio of a cohesive soil which yields a maximum dry unit weight of 17kN/m³…

A: Given- Maximum dry unit weight- γd,max=17 kN/m3,Specific gravity G=2.67, It is needed to find the…

Q: What is the value of the natural water content in percentage? B) What is the value of the in-situ…

A: SOIL MECHANICS:

Q: 9. The degree of compaction of a type of sand in the field is 93.5%.  considering  Yd max =16.98…

A:

Q: The following are given for a natural soil deposit: Moist unit weight, y = 17.8 kN/m³ Moisture…

A: This question is related to Basic properties of Soil From Geotechnical Engineering. In this problem…

Q: Proctor (cm³) 943,9 943,9 943,9 943,9 943,9 943,9 úmido no molde 1673,76 1732,72 1759,94 1755,40…

A: Maximum dry density is always corresponding to optimum moisture content

Q: A soil deposit has a void ratio of 1.4. If the void ratio is reduced to 0.80 by compaction, then the…

A: Given-Void ratio-Void ratio is reduced to 0.80.It is needed to find the % volume loss.

Q: Problem: The moist unit weight of a soil is 18.5 kN/m3. Given that Gs = 2.60 and w = 12%, determine:…

A: given data: YTotal=YMoist=18.5 KN/m3specific gravity (Gs)=2.60water content (w)=12%unit weight of…

Q: The results of a standard compaction test for a soil having a value of (Gs = 2. 5) are shown in the…

A:

Q: From a standard Proctor laboratory sample of soil Gs= 2.70; maximum dry unit weight = 16.4 kN/m3;…

A:

Q: A sandy soil has maximum and minimum dry unit weights of 18.08 kN/m^3 and, 14.46 kN/m^3…

A: step 1-

Q: From a standard Proctor laboratory sample of soil Gs= 2.70; maximum dry unit weight = 16.4 kN/m3;…

A:

Q: Sand is used in the cone is known to have a bulk density of 15.74 kN/m3 Wet weight=20.601 N Dry…

A:

Q: 3. Problem 3. Sand sample has the relative density D, = 0.65, emax = 0.75; e min = 0.52, G₁ = 2.67.…

A:

Q: A soil deposit has a void ratio of 0.9. Its void ratio is reduced to 0.6 by compaction. Determine…

A: Given data- void ratio e1=0.9void ratio e2=0.6To Find-The  reduction of volume by compaction.

Q: Gs= 2.70 A.     What is the void ratio of the soil at Dr= 68%? B.     What is the dry unit weight of…

A:

Q: the modified compaction method for the same soil sample gives .moisture value than the standard…

A: The modified proctor test is also known as heavy compaction test. In the modified proctor test the…

Braced cuts

The braced cut is a method of providing lateral support to the soil in foundation trenches, to prevent the trenches from deformation by the caving in of soil and resisting it from moving laterally. During shallow excavation in firm soil, generally, slopes are provided to resist the caving in of soil. During shallow excavation in soft soil and deep excavation, the chances of caving in of soil increase. Hence, it becomes necessary to make a provision to resist the deformation of trenches due to caving in of soil. The braced cut is the method used for such conditions. The excavation using braced cuts is a bit uneconomical as compared to the traditional open-cut excavation method but provides better safety than the cut excavation method.