Q1: As the figure Shawn for t=0, switch 1 is closed and switch 2 is blä 10 closed 4sec later, find i(t) for t>0 and i * for t=2s, and t=5s 1 =0 62 1= 4 40 V 5H 10 V i(i(t)={(0 ts0, 4(1-e^(-2t) ) Osts4, 2.727+1.273e^(-1.466(t-4) t24) )}A ,3.93A , O 3.022A i(i(t)={(0 t<0, 4(1-e^(-2t) ) Osts4, 2.727+1.273e^(-1.466(t-4) t24) )}A ,3.93A, 4.022A i(i(t)={(0 ts0, 4(1-e^(-2t) ) 0sts4, 2.727+1.273e^(-1.466(t-4) t24) )}A ,2.93A ,

Q1: As the figure Shawn for t=0, switch 1 is closed and switch 2 is blä 10 closed 4sec later, find i(t) for t>0 and i * for t=2s, and t=5s 1 =0 62 1= 4 40 V 5H 10 V i(i(t)={(0 ts0, 4(1-e^(-2t) ) Osts4, 2.727+1.273e^(-1.466(t-4) t24) )}A ,3.93A , O 3.022A i(i(t)={(0 t<0, 4(1-e^(-2t) ) Osts4, 2.727+1.273e^(-1.466(t-4) t24) )}A ,3.93A, 4.022A i(i(t)={(0 ts0, 4(1-e^(-2t) ) 0sts4, 2.727+1.273e^(-1.466(t-4) t24) )}A ,2.93A ,

Electricity for Refrigeration, Heating, and Air Conditioning (MindTap Course List)

10th Edition

ISBN:9781337399128

Author:Russell E. Smith

Publisher:Russell E. Smith

Chapter9: Components For Electric Motors

Section: Chapter Questions

Problem 14RQ

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