For the circult shown, what is the Mesh Current Method equation for mesh D? j2n 20 2+20 1-jn Ic 10490° V 2+j2 N -j20 O (-j2)ID + (2 + j2)(Ip – IA) + (2)(Ip – Ic) = 0 O (-j2)Ip – (2 + j2)(Ip – Ia) – (2)(Ip – Ic) = 0 O (-j2)Ip – (2 + j2)(Ip – Ic) – (2)(Ip – Ia) = 0 O (-j2)ID + (2 + j2)(Ip – Ic) + (2)(Ip – IA) = 0

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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### Circuit Analysis: Mesh Current Method for Mesh D

#### Diagram Description:
The image features a circuit diagram consisting of four meshes, labeled \( I_A \), \( I_B \), \( I_C \), and \( I_D \). This circuit includes resistors with complex impedances and a voltage source. The components are labeled as follows:

- A resistor with impedance \( 1 - j1 \, \Omega \).
- Two resistors with impedance \( 2 + j2 \, \Omega \).
- A resistor with impedance \( j2 \, \Omega \).
- A voltage source of \( 10 \angle 90^\circ \, V \).

Each mesh is indicated by arrows showing the direction of current flow.

#### Question:
For the circuit shown, what is the Mesh Current Method equation for mesh \( D \)?

#### Possible Answers:
1. \( (-j2)I_D + (2 + j2)(I_D - I_A) + (2)(I_D - I_C) = 0 \)
2. \( (-j2)I_D - (2 + j2)(I_D - I_A) - (2)(I_D - I_C) = 0 \)
3. \( (-j2)I_D - (2 + j2)(I_D - I_C) - (2)(I_D - I_A) = 0 \)
4. \( (-j2)I_D + (2 + j2)(I_D - I_C) + (2)(I_D - I_A) = 0 \)

In this exercise, students must apply the mesh current method to solve for the equation corresponding to mesh \( D \). Each answer option represents a potential equation that accounts for the complex impedances and interactions between mesh currents.
Transcribed Image Text:### Circuit Analysis: Mesh Current Method for Mesh D #### Diagram Description: The image features a circuit diagram consisting of four meshes, labeled \( I_A \), \( I_B \), \( I_C \), and \( I_D \). This circuit includes resistors with complex impedances and a voltage source. The components are labeled as follows: - A resistor with impedance \( 1 - j1 \, \Omega \). - Two resistors with impedance \( 2 + j2 \, \Omega \). - A resistor with impedance \( j2 \, \Omega \). - A voltage source of \( 10 \angle 90^\circ \, V \). Each mesh is indicated by arrows showing the direction of current flow. #### Question: For the circuit shown, what is the Mesh Current Method equation for mesh \( D \)? #### Possible Answers: 1. \( (-j2)I_D + (2 + j2)(I_D - I_A) + (2)(I_D - I_C) = 0 \) 2. \( (-j2)I_D - (2 + j2)(I_D - I_A) - (2)(I_D - I_C) = 0 \) 3. \( (-j2)I_D - (2 + j2)(I_D - I_C) - (2)(I_D - I_A) = 0 \) 4. \( (-j2)I_D + (2 + j2)(I_D - I_C) + (2)(I_D - I_A) = 0 \) In this exercise, students must apply the mesh current method to solve for the equation corresponding to mesh \( D \). Each answer option represents a potential equation that accounts for the complex impedances and interactions between mesh currents.
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