Q.7 (b) The a-particle of energy 14 MeV incident on a Ni60 nucleus and form the compound nucleus Zn64 via the following reactions: He + Ni60 → Zn64

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Q.7 (b) The a-particle of energy 14 MeV
incident on a Ni60 nucleus and form the compound
nucleus Zn64 via the following reactions:
He + Ni60 → Zn64
Calculate the excitation energy of Z64 relative to
the ground state Zn64. (Given: M (Ni) = 59.930878u,
M(Zn64) = 63.92914u and M(He) = 4.00260 amu.
Transcribed Image Text:Q.7 (b) The a-particle of energy 14 MeV incident on a Ni60 nucleus and form the compound nucleus Zn64 via the following reactions: He + Ni60 → Zn64 Calculate the excitation energy of Z64 relative to the ground state Zn64. (Given: M (Ni) = 59.930878u, M(Zn64) = 63.92914u and M(He) = 4.00260 amu.
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