A Lithium atom collides with a Hydrogen atom and produces two Alphas (He atoms). The reaction is expressed as: 7Li (Z = 3) + ¹H (Z = 1)→ 4He (Z = 2) + 4He (Z = 2) where the masses are 7Li (Z = 3): 7.016005 u, ¹H (Z = 1): 1.007825 u, 4He (Z = 2): 4.002603 u. The mass difference in the reaction is attributed to the reaction energy which is most nearly what (Express in MeV) (1 u = 931.5 MeV/c²) O 15.37 MeV O 13.57 MeV O 17.35 MeV O 13.35 MeV

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A Lithium atom collides with a Hydrogen atom and produces two Alphas (He atoms).
The reaction is expressed as: 7Li (Z = 3) + ¹H (Z = 1)→ 4He (Z = 2) + 4He (Z = 2) where
the masses are 7Li (Z = 3): 7.016005 u, ¹H (Z = 1): 1.007825 u, 4He (Z = 2): 4.002603
u. The mass difference in the reaction is attributed to the reaction energy which is
most nearly what (Express in MeV)
(1 u = 931.5 MeV/c²)
O 15.37 MeV
O 13.57 MeV
O 17.35 MeV
O 13.35 MeV
Transcribed Image Text:A Lithium atom collides with a Hydrogen atom and produces two Alphas (He atoms). The reaction is expressed as: 7Li (Z = 3) + ¹H (Z = 1)→ 4He (Z = 2) + 4He (Z = 2) where the masses are 7Li (Z = 3): 7.016005 u, ¹H (Z = 1): 1.007825 u, 4He (Z = 2): 4.002603 u. The mass difference in the reaction is attributed to the reaction energy which is most nearly what (Express in MeV) (1 u = 931.5 MeV/c²) O 15.37 MeV O 13.57 MeV O 17.35 MeV O 13.35 MeV
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