Q.4 Consider the Electric power system network shown in Figure (below). Use a voltage base of 13.8Kv and power base of 500 MVA to evaluate the fault current in amperes (Using Bus impedance Matrix) for three phase fault at Bus B? G₁:500 MVA, 13.8 kv, x 0.2 p... G₂:600 MVA, 26 kv, x 0.15 p.u.. Gy: 400 MVA, 13.8 kv, x 0.2 p.u. T₁:500 MVA, 13.8 kv/500 kv, x= 0.1 p.u. T₂:600 MVA, 26 kv/500 kv, x = 0.1 p.u. 7:500 MVA, 13.8 kv/500 kv, x 0.1 p.u. Line AB. X-50 52 Line Bc. x=802 36 G₁ T پیکر G1. t1 50 G2. T2 & T3. G3 38 Gy

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Q.4
Consider the Electric power system network shown in Figure (below). Use a voltage base of 13.8Kv
and power base of 500 MVA to evaluate the fault current in amperes (Using Bus impedance Matrix)
for three phase fault at Bus B?
G₁:500 MVA, 13.8 kv, x
G₂:600 MVA, 26 kv, x
Gy: 400 MVA, 13.8 kv, x
= 0.15 p.u.,
= 0.2 p.t.
T₁:500 MVA, 13.8 kv/500 kv, x = 0.1 p.u.
T₂:600 MVA, 26 kv/500 kv, x= 0.1 p.u.
7:500 MVA, 13.8 kv/500 kv, x=0.1 p.u.
Line ABX 50 £2
x = 80 Ω
Line Bc. X
TI
25
Oty
t1
= 0.2 p.u..
G1.
50
G2.
T2
T3. G3
HO
38
Transcribed Image Text:Q.4 Consider the Electric power system network shown in Figure (below). Use a voltage base of 13.8Kv and power base of 500 MVA to evaluate the fault current in amperes (Using Bus impedance Matrix) for three phase fault at Bus B? G₁:500 MVA, 13.8 kv, x G₂:600 MVA, 26 kv, x Gy: 400 MVA, 13.8 kv, x = 0.15 p.u., = 0.2 p.t. T₁:500 MVA, 13.8 kv/500 kv, x = 0.1 p.u. T₂:600 MVA, 26 kv/500 kv, x= 0.1 p.u. 7:500 MVA, 13.8 kv/500 kv, x=0.1 p.u. Line ABX 50 £2 x = 80 Ω Line Bc. X TI 25 Oty t1 = 0.2 p.u.. G1. 50 G2. T2 T3. G3 HO 38
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