Q.29. Determine, at 298 K, Ar¡Hº, the standardenthalpy of the reaction (1) between hydroquinonewith hydrogen peroxide to produce quinone.C,H4(OH)2(aq) + H2O2(aq) → CGH4O2(aq) + 2 H2O(E) (1)Knowing the standard reaction enthalpies, at 298 K, ofthe following reactions:(2) C6H4(OH)2 (aq) → C6H4O2 (aq) + H2 (g) ;A12H° = + 177.4 kJ mol-1(3) H2 (g) + O2 (g) → H2O2 (aq)A:3H° =-191.2 kJ mol-1(4) H2 (g) + ½0O2 (g) → H20 (g)A:4H° =-241.8 kJ mol-1(5) H2O (g)H2O (€)ArsHº-43.8 kJ mol-1

The question is based on the concept of Hess law. It states that net enthalpy change for the…

Q.29. Determine, at 298 K, A¡H°, the standard enthalpy of the reaction (1) between hydroquinone with hydrogen peroxide to produce quinone. C6H4(OH)2(aq) + H2O2(aq) → C6H4O2(aq) + 2 H2O (€) (1) Knowing the standard reaction enthalpies, at 298 K, of the following reactions:

Q.29. Determine, at 298 K, A¡H°, the standard enthalpy of the reaction (1) between hydroquinone with hydrogen peroxide to produce quinone. C6H4(OH)2(aq) + H2O2(aq) → C6H4O2(aq) + 2 H2O (€) (1) Knowing the standard reaction enthalpies, at 298 K, of the following reactions:

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Q.29. Determine, at 298 K, Ar¡Hº, the standard
enthalpy of the reaction (1) between hydroquinone
with hydrogen peroxide to produce quinone.
C,H4(OH)2(aq) + H2O2(aq) → CGH4O2(aq) + 2 H2O
(E) (1)
Knowing the standard reaction enthalpies, at 298 K, of
the following reactions:
(2) C6H4(OH)2 (aq) → C6H4O2 (aq) + H2 (g) ;
A12H° = + 177.4 kJ mol-1
(3) H2 (g) + O2 (g) → H2O2 (aq)
A:3H° =
-191.2 kJ mol-1
(4) H2 (g) + ½0O2 (g) → H20 (g)
A:4H° =
-241.8 kJ mol-1
(5) H2O (g)
H2O (€)
ArsHº
-43.8 kJ mol-1

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The following table contains some standard enthalpies of formation, AH, at 298 K. Substance diamond graphite carbon tetrachloride carbon tetrachloride carbon tetrafluoride methane carbon monoxide carbon dioxide chlorine gas Cl₂ (g) hydrochloric acid fluorine gas hydrofluoric acid hydrogen oxygen water water hydrogen peroxide hydrogen peroxide ΔΗ (kJ/mol) 1.88 Formula C(s) C(s) 0 CCl4 (g) -106.7 CC14 (1) -139.3 CF4 (g) CH4 (g) -74.8 CO(g) -110.5 -679.9 CO₂(g) -393.5 0 HCl(g) -92.30 F2 (g) 0 HF (g) -268.61 H₂(g) 0 O2 (g) 0 H₂O(g) -241.82 H₂O(1) -285.83 H₂O2(g) -136.10 H₂O2 (1) -187.8
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Q.30. Determine, at 298 K, Δr1H0, the standard enthalpy of the reaction (1) between dinitrogen tetraoxide and hydrazine: (1) N2O4 (g) + 2 N2H4 (l) à 3 N2 (g) + 4 H2O (g) Knowing the standard reaction enthalpies, at 298 K, of the following reactions: (2) NH3 (g)à 1/2 N2 (g) + 3/2 H2 (g) ; Δr2H0 = + 46,19 kJ . mol–1 (3) N2O4 (g) à 2 NO2 (g) ; Δr3H0 = + 58,04 kJ . mol–1 (4) 2 NH3 (g) à N2H (l) + H2 (g) ; Δr4H0 = + 142,80 kJ . mol–1 (5) 2 NO2 (g) + 4 H2 (g) à N2 (g) + 4 H2O (g) ; Δr5H0 = – 1 033,66 kJ . mol–1