17) is this right? Calculate \( \Delta H \) for the following balanced reaction in kJ:\[ 3NO_2 (g) + H_2O (l) \rightarrow 2HNO_3 (aq) + NO (g) \]From the following reactions:\[ 2NO (g) + O_2 (g) \rightarrow 2NO_2 (g) , \quad \Delta H = -116 \text{ kJ} \]\[ 2N_2 (g) + 5O_2 (g) + 2H_2O (l) \rightarrow 4HNO_3 (aq) , \quad \Delta H = -256 \text{ kJ} \]\[ N_2 (g) + O_2 (g) \rightarrow 2NO (g) , \quad \Delta H = +183 \text{ kJ} \]Answer: 138

Given balanced reaction, 3 NO2(g) + H2O(l) → 2 HNO3(aq) + NO(g)

Calculate AH for the following balanced reaction in kJ: 3NO2 (9) + H20 (1) → 2HNO, (aq) + NO (g) From the following reactions: 2 NO (9) +O2 (g) → 2 NO2 (9), AH - -116 kJ 2 N2 (9) + 5 02 (9) + 2 H20 (1) 4 HNO, (aq), N2 (9) + O2 (g) – 2 NO (g), AH = -256 kJ %3D AH = +183 kJ 138

Calculate AH for the following balanced reaction in kJ: 3NO2 (9) + H20 (1) → 2HNO, (aq) + NO (g) From the following reactions: 2 NO (9) +O2 (g) → 2 NO2 (9), AH - -116 kJ 2 N2 (9) + 5 02 (9) + 2 H20 (1) 4 HNO, (aq), N2 (9) + O2 (g) – 2 NO (g), AH = -256 kJ %3D AH = +183 kJ 138

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Solutions

Solutions can be considered as homogeneous mixtures which contain two or more than two chemical substances. The chemical substance which is the greater part is defined as solvent. And the chemical substance that is dissolved in a solvent is referred to as solute. Solution chemistry plays an important role in chemistry since it supports many commercial applications of solutions.

Question

17) is this right?

Calculate \( \Delta H \) for the following balanced reaction in kJ:

\[ 3NO_2 (g) + H_2O (l) \rightarrow 2HNO_3 (aq) + NO (g) \]

From the following reactions:

\[ 2NO (g) + O_2 (g) \rightarrow 2NO_2 (g) , \quad \Delta H = -116 \text{ kJ} \]

\[ 2N_2 (g) + 5O_2 (g) + 2H_2O (l) \rightarrow 4HNO_3 (aq) , \quad \Delta H = -256 \text{ kJ} \]

\[ N_2 (g) + O_2 (g) \rightarrow 2NO (g) , \quad \Delta H = +183 \text{ kJ} \]

Answer: 138

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