Q. 44 : Angular momentum of two bodies of momentum of inertia (I,) and (I) are same (I, > I2). If (E,) and (E2) are rotational kinetic energies them : (a) E1 = E2 (b) Е, > Е, (с) Е, < E, ( d) Ε Ε,
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- The position vector of a particle of mass 1.0 kg as a function of time is given by F= (6f + 10 tj ) m where 7 is in meters and t is in seconds. Determine the angular momentum of the particle about the origin as a function of time (in kg m2/s)? Option 1 Option 2 Option 3 Option 4 Option 5 (20 tj) (120 tj) (60 tj) (30 tj) (240 tj)The angular momentum of a sphere is given by , ?=(―4.59?^3)? + (6.01―1.19?^2)? + (6.26?)? where L has units of kg·m2/s when t is in seconds. What is the net torque on the sphere as a function of time?A particle performing uniform circular motion has angular momentum (L). If its angular frequency is doubled and its kinetic angular energy halved, then the new momentum is : (a) L/4 (b) L/2 (c) 2L (d) 4L
- The figure shows a small piece of clay colliding into a disk. The disk is initially at rest, but can rotate about a pivot fixed at its center. The collision is completely inelastic.1) The disk has mass M = 4.73 kilograms and radius R = 0.755 meters. The clay has mass m = 279 grams and is moving horizontally at vi = 3.66 m/s just before colliding with and sticking to the disk. The clay strikes the edge of the disk at a location of b = 0.505 meters offset from the center of the disk. Note that the size of the clay is negligible compared to the radius of the disk. 2) Calculate the angular velocity (rad/s) of the disk just after the collision.1. A 1571-mg particle is located at the point r = -75.3 cm i - 1876.3 mm j - 63.9 dm k and is moving at a velocity " = -73.1 km/s i - 82.5 hm/s j- 123.4 m/s k. What is the angular momentum (Vector Form and Magnitude) of this particle about the origin?Question 5 unts Given two vectors: M = -3î + 6j – 5k and N = -2î + 3j + k ... The cross product of MxN equals Choose the best answer. A -9i -7j +3k В 21i +13j +3k 9i +7j -3k 13 E No Answer
- Rotating Bracelet. Enrico owns a circular bracelet of mass m = 23 g and diameter d0 = 6.9 cm, which is made of n identical small beads each connected with massless springs of spring constant nk where k = 0.5 N/m. (a) Through some unknown superpower, Enrico manages to make this bracelet levitate and spin horizontally (i.e. axis of rotation is vertical) with an initial angular velocity of ω = 10 rad/s without touching it. This causes the bracelet to lengthen, increasing its diameter. Despite this, Enrico forces the bracelet to maintain a constant angular velocity. Enrico observes that the diameter of this bracelet initially varies, but after a long time, it settles at a constant value d. For large n, what value does d approach? (b) Enrico repeats what he did previously, but this time, the bracelet no longer maintains a constant angular velocity. Again, Enrico observes that the diameter of this bracelet initially varies, but after a long time, it settles at a constant value d. For large…A 9.93 kg particle with velocity ?→=(9.25m/s)?̂ −(6.52m/s)?̂v→=(9.25m/s)î-(6.52m/s)ĵ is at x = 9.15 m, y = 6.63 m. It is pulled by a 9.15 N force in the negative x direction. About the origin, what are (a) the particle's angular momentum, (b) the torque acting on the particle, and (c) the rate at which the angular momentum is changing?Find the magnitude of the reaction at A
- An ice skater is spinning at 5.4 rev/s and has a moment of inertia of 0.44 kg ⋅ m2. Part (a) Calculate the angular momentum, in kilogram meters squared per second, of the ice skater spinning at 5.4 rev/s. Part (b) He reduces his rate of rotation by extending his arms and increasing his moment of inertia. Find the value of his moment of inertia (in kilogram meters squared) if his rate of rotation decreases to 0.75 rev/s. Part (c) Suppose instead he keeps his arms in and allows friction of the ice to slow him to 3.25 rev/s. What is the magnitude of the average torque that was exerted, in N ⋅ m, if this takes 17 s?ASAP for likeQ. 32 : The total energy of rolling ring of mass 'm' and radius 'R' is nid) lo IM (a) (3/2) mv2 (1/2) (c) mv2 (d) (5/2) mv²