1. A 1571-mg particle is located at the point r = -75.3 cm i - 1876.3 mm j- 63.9 dm k and is moving at a velocity = -73.1 km/s i - 82.5 hm/s j- 123.4 m/s k. What is the angular momentum (Vector Form and Magnitude) of this particle about the origin?
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- Q1. Determine the resultant moment +be fig show n below: 200N 70 SOONI need help with this problem. ThanksTwo pieces of space debris drift toward each other, collide, and stick together. The first piece has a mass of 45 kg and a velocity of m/s just before the collision. The second piece has a mass of 65 kg and a velocity of m/s just before the collision. What is the velocity of their center of mass after the collision? O ( 0.73, 0.73, 4.95 ) m/s O ( 3.27, 3.27, 4.05 ) m/s O ( 9.00, -5.00, 9.00 ) m/s O ( -0.99, -0.99, 11.50 ) m/s O None of the above
- 3. The figure to the right shows a rod that is connected to a frictionless table through a pin-labeled by A -placed through the center of it. (You are looking down on the table.) The rod has mass m and length l. Although the rod is initially at rest, it can rotate freely (without friction) about the pin. A small particle with mass m/3, and moving with an initial velocity vo vo collides with the end of the rod. After the collision the mass stops moving, and the rod starts rotating with angular velocity w. I would strongly recommend that you draw a free body diagram for the rod in parts a and b. a. Linear momentum is not conserved for this collision. Explain in detail why. b. Angular momentum is conserved about the pivot. Explain in detail why. c. What is w? Express it in terms of vo, and l. d. Is energy conserved in the collision? Justify your answer by calculating the change in energy of the system in the collision. e. After a time T after the collision the rod will rotate around and…#1. Due to the conservation of angular momentum, moving mechanical parts in a spacecraft can affect the orientation and rate of angular rotation of the craft. Let us, crudely speaking, model Voyager II as a uniform disk with a mass of 720 kg and an effective radius of 1.0 meters. What is the moment of inertia of Voyager II under these assumptions? A.720kgm^2 B.580kgm^2 C.360kgm^2 D.180kgm^2 #1-1. Suppose the spacecraft in #1 is initially not rotating as a whole, and none of its compo- nents are rotating. A data tape spool with a moment of inertia of 1.25 × 10^−4 kg m^2 begins to spin at a rate of 15.5 Rad/s. What is the angular momentum of the spacecraft as a whole? A. 3.88×10^−3 kg·m^2/s B. 1.94×10^−3 kg·m^2/s C. 9.69×10^−4 kg·m^2/s D. 0.0 kg·m^2/s # 1-3. As the result of the tape spool operation, what is the magnitude of the angular speed of the spacecraft in #1-1 as a whole? A. 0.0 Rad/s B. 5.38 × 10^−6 Rad/s C. 1.07 × 10^−5 Rad/s D. 2.14 × 10^−5 Rad/s8. The image below depicts a street light standard that has been blown off of vertical by high winds during storm. A force of 1000N is being applied to the standard in order to "upright" the standard. Determine the magnitude and sense of the Moment about point A at the instant depicted. N-m. Be sure to include whether the Moment is Moment = Positive or Negative for this 2D problem. B 6 m 75° 3 m
- A 1140 kg1140 kg car has just passed a diner. The closest the car came to the diner was ?=24.5 mR=24.5 m, but the car has driven another ?=30.7 mx=30.7 m in the 2.65 s2.65 s elapsed since then. If the car travels at constant speed, what is the current magnitude ?L of the angular momentum of the car about the diner?The member shown below is fixed at O and its dimensions are h1h1 = 1.10 mm, h2h2 = 0.20 mm, and ww = 0.50 mm. A force F of magnitude F=160N is applied at point C. Determine the magnitude of the moment of the force about point O.15 75 Vb+w だ h A block of mass m,-1.28 kg slides to the right at a speed of 2.46 m/s on a frictionless horizontal surface, as shown in the figure. It "collides" with a wedge of mass mw, which moves to the left at a speed of 1.13 m/s. The wedge is shaped so that the block slides seamlessly up the Teflon (frictionless!) surface, as the two come together. Relative to the horizontal surface, block and wedge are moving with a common velocity Vb+w at the instant the block stops sliding up the wedge. a) If the block's center of mass rises by a distance h = 0.38 m, what is the mass of the wedge? The gravitational acceleration is g = 9.8 m/s². Express your answer in kg.