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- can I get an explanation on how to do these? thankyouHgSO4 H2SO4, H20 1T (1) Br H2O2, NaOH 10 NaNH2 BH3, THE H =H 1S NH3 H20 HCI (1 equiv.) diethyl ether 1V 1W Br2 (m) MgBr (H,C=CH),CULI NaOCI ТСРВА > 1X 1Y > 1Z CH3COOH 1AA diethyl ether SoCI2, pyridine diethyl ether 1ABHO - CH, НО - ОН I CH_ - :0: solute CH ОН - NaCl ОН I CH - CH ОН - :0: || с :0: || - · C — CH2 — CH2 — C — ОН н Which is the better solvent? Н н C | H 1 C C 1 Н CH3- H2O CH₂OH C ||| C CH3(CH2), ОН :0: || S о- CH3 CH₂CH₂OH Н Н
- H3C CH3 CH3 CH 3 excess Na2Cr2O7 H₂SO COOH A COOH COOH се -CH3 COOH CH3 C H3C B COOHH3C-CH₂-CH₂-C-OH APR 27 200 CH3–CH2–NH, heat tv H₂O + ST4. The scheme below shows the reaction of a ketone, 2-propanone with methanol. ОН :0 : || CH;-C-CH3 : ОН + H - Н CH,-C-CH3 CH;-C-CH3 N step 1 step 2 step 3 P CH;OH CH3 CH;OH step 4 OCH, CH,-C-CH3 H - H,0 R CH;-C-CH3 step 7 step 6 step 5 OCH3 OCH; i) Write the missing structures (N, O, Q and R) in the above reaction scheme. ii) Name the class of compounds P and S belong to? iii) This is an acid catalyzed reaction. What does this statement mean? iv) Draw the arrow diagram in step 6 to show how intermediate R is formed? Write the equation for this step ONLY. v) Steps 3 and 7 involve loss of a proton from the intermediate ions. Why is this step necessary?