Q 7: An electronic system with 12 -electrons (all of them in conjugation) can be treated as aparticle in a 2-D box of size of 3 Å x 6 Å. Calculate the wavelength corresponding to the lowestenergy electronic transition for this system.The expression for the energy of a 2-D box with sides of length a and b is(n²Enginy= 2²2 (22/2+a²+n²b²where nx and ny are quantum numbers (1, 2, 3, 4, etc.). These two quantum numbers are independentof each other and do not have to be equal, though they will be equal for some energy levels, forexample the lowest energy state (the ground state) is E11. Some of the energy levels will degenerate.

We are given a 2D box with dimensions containing electrons in conjugation. The lowest energy…

Answered: Q 7: An electronic system with 12…

Similar questions

An electron is in a 3p state in the hydrogen atom, given that the expectation value is 12.5a_0 What is the probability of finding the electron within +/- a_0 of your expectation value. (That is, in the range (r − a_0) < r < (r+a_0) where r is the expectation value from above. The answer should be 0.1991.
-2r/rB dr. Find the probability that the r2e The radial probabiliity density for an electron in the 1s orbital is given by P(r) electron is found between 1.22 rg and (1.22+0.001)r;. Give you answer to two decimal places in exponential notation. Round your answer to 2 decimal places. Add your answer
A quantum simple harmonic oscillator consists of an electron bound by a restoring force proportional to its position relative to a certain equilibrium point. The proportionality constant is 8.79 N/m. What is the longest wavelength of light that can excite the oscillator? nm
A quantum system has a ground state with energy Eo = 0 meV and a 2-fold degenerate excited state with energy E₁ = 50 meV. E1 Calculate the probability of finding the system in its ground state when it is at T = 300 K. Select one: O a. 0.78 O b. 0.22 O c. 1 O d. 0.87
2-d particle in a box problem. Benzene can be treated as a 2-d box with sides of length 3.5 Å and containing 6 7-electrons. What wavelength of light would be required to promote an electron from the ground state to the first excited electronic state? Answer 135 nm Hint: Use the result for the energy of a particle in a 2-d box: 7²h? Y + (5.1) Nx,Ny 2me L? L3 1,2, 3... and те 9.8 × 10-31kg You need with ng = 1,2, 3... and ny the first 3 energy levels for the 6e¯, and the transition energy will be the energy between the HOMO and the LUMO (the 4th energy level).
Physics 1. Derive the expression ε(ω)=1- ωp 2 / ω2 , ωp2 =ne2 /ε0m for the dielectric constant as a function of ω for a free electron gas of number density n. 2. Show clearly that metals are opaque to light for which ω is less than ωp. 3. Calculate the wavelength cutoff for Na metal if the volume of a primitive unit cell in Na is 35×10-30 m3 how to solve this problem?