The Balmer series for the hydrogen atom corresponds to electronic transitions that terminate in the state with quantum number n = 2 as shown in the figure below. Consider the photon of longest wavelength. corresponding to a transition shown in the figure. ENERGY n 6 2. Balmer series (a) Determine its energy. eV (b) Determine its wavelength. nm E (eV) 0.00 (d) Find its wavelength. nm -0.378 -0.544 2 -0.850 4 -1.512 -3.401 Consider the spectral line of shortest wavelength corresponding to a transition shown in the figure. (c) Find its photon energy. eV (e) What is the shortest possible wavelength in the Balmer series? nm
The Balmer series for the hydrogen atom corresponds to electronic transitions that terminate in the state with quantum number n = 2 as shown in the figure below. Consider the photon of longest wavelength. corresponding to a transition shown in the figure. ENERGY n 6 2. Balmer series (a) Determine its energy. eV (b) Determine its wavelength. nm E (eV) 0.00 (d) Find its wavelength. nm -0.378 -0.544 2 -0.850 4 -1.512 -3.401 Consider the spectral line of shortest wavelength corresponding to a transition shown in the figure. (c) Find its photon energy. eV (e) What is the shortest possible wavelength in the Balmer series? nm
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Transcribed Image Text:The Balmer series for the hydrogen atom corresponds to electronic transitions that terminate in the state with quantum number n = 2 as shown in the figure below. Consider the photon of longest wavelength
corresponding to a transition shown in the figure.
ENERGY
n
8
6543
2
Balmer
series
(a) Determine its energy.
eV
(b) Determine its wavelength.
nm
(d) Find its wavelength.
nm
E (eV)
0.00
-0.378
-0.544 2
-0.850 4
-1.512
Consider the spectral line of shortest wavelength corresponding to a transition shown in the figure.
(c) Find its photon energy.
eV
-3.401
(e) What is the shortest possible wavelength in the Balmer series?
nm
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