Q (2): A laboratory experiment has been executed to calculate the thermal conductivity of a specimen.The specimen is a bar with (Diameter= 0.04 m) and (length = 0.06 m). At steady state condition, thefollowing data have been recorded:Voltage(V) Current(A)80.8T₁ (°C)46.8T₂ (°C) T3 (°C)42.234.6T. (°C)31.4By taking into consideration that the temperature changes linearlywith position, refer to the figure aside, and calculatehe thermal conductivity for the specimen (intermediate section).T₂T₂The faceTold faceT₂T₂6 cm4 cm6 cm4 cm6 cmHot sectionInt. sectionCold section

Given: The diameter of the bar is d=0.04 m The voltage is V= 8 volt The current is I=0.8 A Formula…

Q (2): A laboratory experiment has been executed to calculate the thermal conductivity of a specimen. The specimen is a bar with (Diameter= 0.04 m) and (length = 0.06 m). At steady state condition, the following data have been recorded: Voltage(V) Current(A) 8 0.8 T₁ (°C) T₂ (°C) T₁ (°C) T4 (°C) 46.8 42.2 34.6 31.4 By taking into consideration that the temperature changes linearly with position, refer to the figure aside, and calculate he thermal conductivity for the specimen (intermediate section). T₁ T₂ The face Trold face T₁ 6 cm 4 cm 6 cm 4 cm 6 cm Hot section Int, section Cold section

Q (2): A laboratory experiment has been executed to calculate the thermal conductivity of a specimen. The specimen is a bar with (Diameter= 0.04 m) and (length = 0.06 m). At steady state condition, the following data have been recorded: Voltage(V) Current(A) 8 0.8 T₁ (°C) T₂ (°C) T₁ (°C) T4 (°C) 46.8 42.2 34.6 31.4 By taking into consideration that the temperature changes linearly with position, refer to the figure aside, and calculate he thermal conductivity for the specimen (intermediate section). T₁ T₂ The face Trold face T₁ 6 cm 4 cm 6 cm 4 cm 6 cm Hot section Int, section Cold section

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

q1 answer in 10 minutes
i need the answer quickly
Three engineers are independently estimating the spring constant of a spring, using the linear model specified by Hooke’s law. Engineer A measures the length of the spring under loads of 0, 1, 2, 4, and 6 lb, for a total of five measurements. Engineer B uses the same loads, but repeats the experiment twice, for a total of 10 independent measurements. Engineer C uses loads of 0, 2, 4, 8, and 12 lb, measuring once for each load. The engineers all use the same measurement apparatus and procedure. Each engineer computes a 95% confidence interval for the spring constant. If the width of the interval of engineer A is divided by the width of the interval of engineer B, the quotient will be approximately _____. Numeric Response
Creep exercises The following data in the table below was obtained a from rupture test. Stress (MPa) Temperature (°C) Rupture time (hr) T 550 580 0.75 550 555 5.5 550 540 19.2 550 525 62.0 70 760 2.05 70 730 8.2 70 700 36.5 70 675 134 Assume: C = 46 Establish whether the Larson-Miller parameter is valid for both stresses (550 and 70 MPa). Was there a change in creep mechanism when changing the stress from 550 to 70 MPa during rupture test? Motivate your answer with the aid of calculation.
Heat is being generated in a fuel element at a volumetric heat generation rate of q′′′ = 1300 kW/m3. The fuel element is a rectangular parallelepiped of thickness 2 cm with a height of 2 m and width of 1 m. The fuel thermal conductivity is k = 3.5 W/m·C. Find the rate of heat transfer from the fuel element at steady state condition. [Ans.: 52 kW].
. 2) A following figure and table display creep test data obtained from a uniaxial specimen having an initial gauge length of 2 cm. Calculate the steady-state creep rate. Length |(cm) 2.3 Time | (h) 2.25 2.004 2.2 100 2.010 200 2.020 400 2.030 1000 2000 2.045 2.075 2.1 2.05 4000 2.135 6000 2.193 7000 2.230 1.95 8000 2.300 1000 2000 3000 4000 5000 6000 7000 8000 Time (h) (rupture) | Length between the gauge marks (cm) 2.
0.6. The resistance of a certain size of copper wire is given as. R = Ro[1 + a(T-20)] %3D where Ro-60+0.3 percent is the resistance at 20°C, a=0.004°C-1+1 percent is the temperature coefficient of resistance, and the temperature of the wire is T=30°C + 1 percent. Calculate the resistance of wire and its uncertainty.
plz ansswer q1 part e velocity is in km/h not in m/s
Thermodynamics is extensively used in engineering field. The following polynomial can be used to relate the zero-pressure specific heat of dry air c, kl/(kg K) to temperature (K) c, = 0.99403 + 1.671 x 104T +9.7215 x 10-872-9.5838 x 10-"T³ + 1.9520 x 10-4T Which of the following(s) is/are the correct method to determine the temperature that corresponds to a specific heat of 1.1 kl/(kg K). (Choose all that applyl) O A) Gauss-Seidel Method O B) Lagrange Interpolation O C) Newton-Divided Difference O 0) Bisection Method Newton Method
1. A spring mass system serving as a shock absorber under a car's suspension, supports the M 1000 kg mass of the car. For this shock absorber, k = 1 × 10°N /m and c = 2 × 10° N s/m. The car drives over a corrugated road with force %3| F = 2× 10° sin(@t) N . Use your notes to model the second order differential equation suited to this application. Simplify the equation with the coefficient of x'" as one. Solve x (the general solution) in terms of w using the complimentary and particular solution method. In determining the coefficients of your particular solution, it will be required that you assume w – 1z w or 1 – o z -w. Do not use Matlab as its solution will not be identifiable in the solution entry. Do not determine the value of w. You must indicate in your solution: 1. The simplified differential equation in terms of the displacement x you will be solving 2. The m equation and complimentary solution xe 3. The choice for the particular solution and the actual particular solution x,…
The rapid progress of engineering design and information technology has caused difficulties in analyzing system reliability. Because of the increased complexity in system reliability structure (component/subsystem interfaces), many unexpected failure modes could occur, and their behaviors are interdependent. At a system’s design and development stage, the main challenge in analyzing a complex system is the failure uncertainty introduced by the incomplete knowledge of the system. This makes it hard to decompose system reliability into subsystem/component reliability in a deterministic manner, such as series or parallel systems. As a result, some common reliability analysis tools such as fault tree (FT) and reliability block diagram (RBD) become inadequate. Do you agree, why or why not? Are there any other approaches to system reliability assessment beside these tools at the early system’s design and development stage (what are these approaches)?