Problems 6-10 refer to the following diagram and situation. An electron (with chargeq = -1.60 × 10-19 C and mass m = 9.11 × 10-3¹ kg) has an initial speedVo = 2.80 x 107 m/sec. The electron enters midway between two horizontal plates of lengthL = 0.0650 m. The distance between the two plates is d = 0.0130 m and the potentialdifferent between the two plates is 250 V. Since the electric field between the two plates isconstant, the electric field can be found with the equation E = AV/d. You may ignore gravity.Lvo++ + + + + + +10Problem 6:When the electron is between the two plates, what is the vertical acceleration of the electron?a. 1.38 x 1015 mb. 3.38 x 1015 msec²C.sec²d. 7.38 x 1015msec5.38 x 1015 msec²Problem 7:At what time does the electron leave the region between the two plates?a. 2.32 x 10-⁹ sec b. 4.32 x 10-⁹ secC. 6.32 x 10-⁹ secProblem 8:What is the horizontal speed of the electron when it leaves the region between the two plates?a. 2.80 x 10²b. 4.80 x 107 mC.d. 8.80 x 107 msecsec6.80 x 107 msecmsec²d. 8.32 x 10-⁹ secProblem 10:At what angle does the electron leave the region between the two plates?a. 11.6°b. 13.6°c. 15.6°Problem 9:What is the vertical speed of the electron when it leaves the region between the two plates?a. 1.84 x 106 mb. 3.84 x 106 mc. 5.84 x 106 md. 7.84 x 106secsecsecd. 17.6°msec

Answered: Image /qna-images/answer/40b0500b-4d59-44be-b745-4a0dd6ae5c27.jpg

q = -1.60 × 10-19 C and mass m = 9.11 × 10-³1 kg) has an initial speed Vo = 2.80 x 107 m/sec. The electron enters midway between two horizontal plates of length L = 0.0650 m. The distance between the two plates is d = 0.0130 m and the potential different between the two plates is 250 V. Since the electric field between the two plates is constant, the electric field can be found with the equation E = AV/d. You may ignore gravity. L Vo d + + + + + + + + Problem 6: When the electron is between the two plates, what is the vertical acceleration of the electron? a. 1.38 x 1015 m b. 3.38 x 1015 m d. 7.38 x 1015 m sec² sec² sec² C. 5.38 x 1015 m sec²

q = -1.60 × 10-19 C and mass m = 9.11 × 10-³1 kg) has an initial speed Vo = 2.80 x 107 m/sec. The electron enters midway between two horizontal plates of length L = 0.0650 m. The distance between the two plates is d = 0.0130 m and the potential different between the two plates is 250 V. Since the electric field between the two plates is constant, the electric field can be found with the equation E = AV/d. You may ignore gravity. L Vo d + + + + + + + + Problem 6: When the electron is between the two plates, what is the vertical acceleration of the electron? a. 1.38 x 1015 m b. 3.38 x 1015 m d. 7.38 x 1015 m sec² sec² sec² C. 5.38 x 1015 m sec²

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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