[Python question: submit a print-out of your answer] We have shown that the harmonic series 1 diverges because its sequence of partial sums Sk = n=1 is unbounded above. Hence, given any MER, there exists some k EN such that Sk> M. By experimenting with Python, find the smallest k EN such that (a) sk > 4, (b) Sk > 8, (c) Sk > 12, (d) sk > 16.
[Python question: submit a print-out of your answer] We have shown that the harmonic series 1 diverges because its sequence of partial sums Sk = n=1 is unbounded above. Hence, given any MER, there exists some k EN such that Sk> M. By experimenting with Python, find the smallest k EN such that (a) sk > 4, (b) Sk > 8, (c) Sk > 12, (d) sk > 16.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![2. [Python question: submit a print-out of your answer]
We have shown that the harmonic series diverges because its sequence of
partial sums
$k =
k
n=1
n
n=1
is unbounded above. Hence, given any MER, there exists some k EN such that
Sk> M. By experimenting with Python, find the smallest kN such that
(a) sk > 4,
(b) Sk > 8,
(c) Sk > 12,
(d) Sk > 16.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7dd22a7c-6880-4a63-9133-40fb48f40bc4%2Fc4e31e1e-16df-4730-a63d-2ec16bd49517%2Fwunbehc_processed.jpeg&w=3840&q=75)
Transcribed Image Text:2. [Python question: submit a print-out of your answer]
We have shown that the harmonic series diverges because its sequence of
partial sums
$k =
k
n=1
n
n=1
is unbounded above. Hence, given any MER, there exists some k EN such that
Sk> M. By experimenting with Python, find the smallest kN such that
(a) sk > 4,
(b) Sk > 8,
(c) Sk > 12,
(d) Sk > 16.
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