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EXERCISE 7: Sequence: The first term of a sequence is a1 = sin(1). The next terms are: a2 = min{a1,sin(2)} (the smallest of a1 and sin 2), az = min{a2, sin(3)} (the smallest of az and sin 3),... an+1 = min{an, sin(n + 1)} (the smallest of an and sin(n +1)). Is this sequence {an} converging or diverging?

EXERCISE 7: Sequence: The first term of a sequence is a1 = sin(1). The next terms are: a2 = min{a1,sin(2)} (the smallest of a1 and sin 2), az = min{a2, sin(3)} (the smallest of az and sin 3),... an+1 = min{an, sin(n + 1)} (the smallest of an and sin(n +1)). Is this sequence {an} converging or diverging?

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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EXERCISE 7: Sequence: The first term of a sequence is a1 = sin(1). The next terms are: a2 = min{a1,sin(2)} (the smallest of a1 and sin 2), az = min{a2, sin(3)} (the smallest of az and sin 3),... an+1 = min{an, sin(n + 1)} (the smallest of an and sin(n +1)). Is this sequence {an} converging or diverging?
Transcribed Image Text:EXERCISE 7: Sequence: The first term of a sequence is a1 = sin(1). The next terms are: a2 = min{a1,sin(2)} (the smallest of a1 and sin 2), az = min{a2, sin(3)} (the smallest of az and sin 3),... an+1 = min{an, sin(n + 1)} (the smallest of an and sin(n +1)). Is this sequence {an} converging or diverging?
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