P(X₁ = x₁) * ∏ᵢ₌₂³ P(Xᵢ = xᵢ | X₁ = x₁, ..., Xᵢ₋₁ = xᵢ₋₁).
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Hello, I have a question regarding your second solution. In our lecture we had this formula for the conditional probability: P(X₁ = x₁) * ∏ᵢ₌₂³ P(Xᵢ = xᵢ | X₁ = x₁, ..., Xᵢ₋₁ = xᵢ₋₁).
This seems different from your Formular.
Can you update the solution with the correct formula?
Thank you.
Step by step
Solved in 4 steps
- By rewnting the formula for the multiplication rule, you can write a formula for finding P(A and B) P(A) conditional probabilities. The conditional probability of event B occurring, given that event A has occurred, is P(B A)= Use the information below to find the probability that a flight departed on time given that it arrives on time. The probability that an airplane flight departs on time is 0.91. The probability that a flight arrives on time is 0.89. The probability that a flight departs and arrives on time is 0.82. The probability that a flight departed on time given that it arrives on time is. (Round to the nearest thousandth as needed.) esThe probability that Luis will pass his statistic test is 0.62. Find the probability that he will fail his statistic test.The probability of winning the "grand prize" at a fortune spinning wheel is p=0.2. If you spin the wheel 100 times how many grand prizes can you expect to win
- How are your grades? In a recent semester at a local university, 700 students enrolled in both Statistics I and Psychology I. Of these students, 77 got an A in statistics, 68 got an A in psychology, and 35 got an A in both statistics and psychology. Round the answers to four decimal places, as needed. Part 1 of 2 (a) Find the probability that a randomly chosen student got an A in statistics or psychology or both. The probability that a randomly chosen student got an A in statistics or psychology or both is Part 2 of 2 (b) Find the probability that a randomly chosen student did not get an A in psychology. The probability that a randomly chosen student did not get an A in psychology is X XFind the probability that z is greater than -1.72.A physician wants to see if there was a difference in the average smokers' daily cigarette consumption after wearing a nicotine patch. The physician set up a study to track daily smoking consumption. In the study, the patients were given a placebo patch that did not contain nicotine for 4 weeks, then a nicotine patch for the following 4 weeks. Test to see if there was a difference in the average smoker's daily cigarette consumption using α = 0.01. The hypotheses are: H0 : μD = 0 H1 : μD ≠ 0 t-Test: Paired Two Sample for Means Placebo Nicotine Mean 18.75 12.3125 Variance 66.599 34.6667 Observations 16 16 Pearson Correlation 0.6105 Hypothesized Mean Difference 0 df 15 t Stat 3.5481 P(T<=t) one-tail 0.0126 t Critical one-tail 2.6025 P(T<=t) two-tail 0.0252 t Critical two-tail 2.9467 What is the correct p-value? Question 1 options:…
- By rewriting the formula for the multiplication rule, you can write a formula for finding P(A and B) conditional probabilities. The conditional probability of event B occurring, given that event A has occurred, is P(B A) = Use the information below to find the probability that a flight P(A) departed on time given that it arrives on time. The probability that an airplane flight departs on time is 0.89. The probability that a flight arrives on time is 0.87. The probability that a flight departs and arrives on time is 0.83. The probability that a flight departed on time given that it arrives on time is (Round to the nearest thousandth as needed.)1 Please explain in clear detail, showing all steps for the MATH. How do you use this formula to get the answeR 0.104? Thank you!! Step 4 So construct the probabilities: Pr(X ≥ 3) = Pr(X = 3) + Pr(X = 4) + Pr(X (3)0.25³ X 0.75² + (5) 0.25 × 4 5 0.255 × 0.75⁰ + 5) 0.25¹ × 0.75¹ X 5 = 0.104 4 of 6You are driving on a toll highway from King Road to Queen Road (a 50 km drive) in 25 minutes .Two weeks later, you get a speeding ticket in the mail. How can the ticket be justified? Please use mean value theorem to solve.
- When rolling two fair six-sided dice, getting a pair of 1s is called “snake eyes.” The probability of getting “snake eyes” on any roll is 1/36. Suppose that a game player rolls the two dice 80 times. Let X = the number of rolls that result in “snake eyes.” Find P(X = 2). Interpret this value in context.Side-by-Side The battery manufacturer Varta sells a car battery with 800 Find the probability that 9 or fewer cars will start. cold-cranking amps and advertises great performance even in bitterly cold weather. Varta claims that after sitting on a (Use decimal notation. Use Appendix Table 1. Give your answer to four decimal places.) frozen Minnesota lake for 10 days at temperatures below 32°F, this battery will still have enough power to start a car. Suppose the actual probability of starting a car following this experiment is 0.75, and 15 randomly selected cars probability: (equipped with this battery) are subjected to these grueling conditions.The probability that an event will happen isP(E)=0.22.Find the probability that the event will not happen.
