Machine Breakdown Example • S={E= electrical, M = mechanical, U = misuse} P(E)= 0.2, P(M) = 0.5, P(U) = 0.3 ● X₁ = #breakdowns due to electrical failure X₂ = #breakdowns due to mechanical failure X3 = =#breakdowns due to operator misuse ➤What is the probability of 2 electrical failures, 4 mechanical failures, and 3 misuses? ƒ(x₁,x₂,.x3;9,0.2,0.5,0.3) = 9 (0.2) (0.5)*(0.3)³ 2,4,3 17
Machine Breakdown Example • S={E= electrical, M = mechanical, U = misuse} P(E)= 0.2, P(M) = 0.5, P(U) = 0.3 ● X₁ = #breakdowns due to electrical failure X₂ = #breakdowns due to mechanical failure X3 = =#breakdowns due to operator misuse ➤What is the probability of 2 electrical failures, 4 mechanical failures, and 3 misuses? ƒ(x₁,x₂,.x3;9,0.2,0.5,0.3) = 9 (0.2) (0.5)*(0.3)³ 2,4,3 17
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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