P²(x) = (3x²-1), ²2²0) = -(1-x²) ¹² (32²-1)]=-3x√1-x²₁ 1/2 d dx P²00)=(1-²) () [(₁2²-1)] =3(1-2). dx
P²(x) = (3x²-1), ²2²0) = -(1-x²) ¹² (32²-1)]=-3x√1-x²₁ 1/2 d dx P²00)=(1-²) () [(₁2²-1)] =3(1-2). dx
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Introduction to Quantum Mechanics
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![P²(x) = (3x²-1), ²2²0) = -(1-x²) ¹² (32²-1)]=-3x√1-x²₁
1/2 d
dx
P²00)=(1-²) () [(₁2²-1)] =3(1-2).
dx](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9e037703-16f1-40aa-84c7-090a0ffa9ec0%2F905d38db-f78a-44e8-b91c-36661f13a8e3%2Fmu69qxaol.jpeg&w=3840&q=75)
Transcribed Image Text:P²(x) = (3x²-1), ²2²0) = -(1-x²) ¹² (32²-1)]=-3x√1-x²₁
1/2 d
dx
P²00)=(1-²) () [(₁2²-1)] =3(1-2).
dx
Transcribed Image Text:Po=1
Pl=-sin 0
P₁ = cos 0
P2=3 sin² 0
P₁=-3 sin 0 cos 0
Po=(3 cos² 0-1)
P3=-15 sin 0(1-cos²0)
P3= 15 sin²0 cos
P}=-3-sin 0(5 cos² 0-1)
P=½ (5 cos³ 0-3 cos 6)
0)
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