Provide a detailed mechanism for the SN1 reaction below. Show how both products are formed. Use arrows to show the movement of electrons and be sure to show all formally charged atoms.  I need help with this practice problem, thank you!

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Provide a detailed mechanism for the SN1 reaction below. Show how both products are formed. Use arrows to show the movement of electrons and be sure to show all formally charged atoms. 

I need help with this practice problem, thank you!

**Reaction of 1-Bromo-1-methylcyclohexane with Methanol**

In this chemical reaction, 1-bromo-1-methylcyclohexane reacts with methanol (\(CH_3OH\)) to form 1-methoxy-1-methylcyclohexane and hydrobromic acid (\(HBr\)).

### Reaction Details:

- **Starting Material:**
  - 1-Bromo-1-methylcyclohexane: This compound consists of a cyclohexane ring with a bromine atom and a methyl group attached to the same carbon.

- **Reagent:**
  - Methanol (\(CH_3OH\)): A simple alcohol used as a reagent in this reaction.

- **Product:**
  - 1-Methoxy-1-methylcyclohexane: This compound is formed when the bromine atom in the starting material is replaced by a methoxy group (\(OCH_3\)).
  - Hydrobromic Acid (\(HBr\)): A byproduct of this substitution reaction.

### Mechanism:

This reaction likely proceeds via an \(S_N1\) mechanism, where the bromine atom leaves first, forming a carbocation intermediate. The methanol then acts as a nucleophile, attacking the positively charged carbon to form the ether product.

This transformation is a classic example of a nucleophilic substitution reaction, showcasing the conversion of an alkyl halide to an ether using an alcohol.
Transcribed Image Text:**Reaction of 1-Bromo-1-methylcyclohexane with Methanol** In this chemical reaction, 1-bromo-1-methylcyclohexane reacts with methanol (\(CH_3OH\)) to form 1-methoxy-1-methylcyclohexane and hydrobromic acid (\(HBr\)). ### Reaction Details: - **Starting Material:** - 1-Bromo-1-methylcyclohexane: This compound consists of a cyclohexane ring with a bromine atom and a methyl group attached to the same carbon. - **Reagent:** - Methanol (\(CH_3OH\)): A simple alcohol used as a reagent in this reaction. - **Product:** - 1-Methoxy-1-methylcyclohexane: This compound is formed when the bromine atom in the starting material is replaced by a methoxy group (\(OCH_3\)). - Hydrobromic Acid (\(HBr\)): A byproduct of this substitution reaction. ### Mechanism: This reaction likely proceeds via an \(S_N1\) mechanism, where the bromine atom leaves first, forming a carbocation intermediate. The methanol then acts as a nucleophile, attacking the positively charged carbon to form the ether product. This transformation is a classic example of a nucleophilic substitution reaction, showcasing the conversion of an alkyl halide to an ether using an alcohol.
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