c) Explain why the room temperature ¹H NMR spectrum of AlMe3 consists of one singlet, but at low temperature, the spectrum consists of two singlets in a 2:1 ratio.

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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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a) Draw the structure of AlMe3. Use MO theory to explain any unusual features in
the connectivity of this compound.
b) How does the structure of AIMes compare to BMe3? Explain why a difference
is observed.
c) Explain why the room temperature ¹H NMR spectrum of AlMe3 consists of one
singlet, but at low temperature, the spectrum consists of two singlets in a 2:1
ratio.
d) The reaction below shows the 1:1 stoichiometric reaction of AlMe3 with
ArNH2 gives a new planar, cyclic compound 1 and a gas 2. The molecular
weight of 1 is 651.87 and gives a single peak in the 27AI NMR spectrum. The
gas 2 has a molecular weight of 16.04.
NH₂
+ AIMe3
1 + 2 (g)
ArNH₂
(i) Using the data given to explain your answer, identify 1 and 2 and write a
balanced equation for the reaction.
(ii) Discuss any possible T-bonding present in compound 1 and draw the
most bonding T-molecular orbital.
(iii) Compare how the T-bonding in 1 may differ from that in the analogue with
Al is replaced by B. Use your answer to explain which compound is the
stronger Lewis acid.
Transcribed Image Text:a) Draw the structure of AlMe3. Use MO theory to explain any unusual features in the connectivity of this compound. b) How does the structure of AIMes compare to BMe3? Explain why a difference is observed. c) Explain why the room temperature ¹H NMR spectrum of AlMe3 consists of one singlet, but at low temperature, the spectrum consists of two singlets in a 2:1 ratio. d) The reaction below shows the 1:1 stoichiometric reaction of AlMe3 with ArNH2 gives a new planar, cyclic compound 1 and a gas 2. The molecular weight of 1 is 651.87 and gives a single peak in the 27AI NMR spectrum. The gas 2 has a molecular weight of 16.04. NH₂ + AIMe3 1 + 2 (g) ArNH₂ (i) Using the data given to explain your answer, identify 1 and 2 and write a balanced equation for the reaction. (ii) Discuss any possible T-bonding present in compound 1 and draw the most bonding T-molecular orbital. (iii) Compare how the T-bonding in 1 may differ from that in the analogue with Al is replaced by B. Use your answer to explain which compound is the stronger Lewis acid.
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