**Title:** Curved Arrow Mechanism for SN1 Reaction**Instruction:**Provide a curved arrow mechanism for the following reaction.**Reaction Description:**- **Starting Material:** The starting material is a secondary alkyl chloride, displaying a wedge bond to a chlorine atom. - **Reagent:** Ethanol (CH₃CH₂OH) is used as the reagent.- **Product:** The product is an ether, with the ether oxygen forming a bond at the position where chlorine was initially attached. The product is shown with a solid and wedge line indicating stereochemistry. The notation "+ enantiomer" indicates the formation of a racemic mixture.**Mechanism Explanation:**1. **Ionization:** The alkyl chloride undergoes ionization, losing the chloride ion and forming a carbocation.2. **Nucleophilic Attack:** Ethanol acts as a nucleophile and attacks the carbocation, leading to the formation of the ether.3. **Stereochemistry:** The result is a racemic mixture of enantiomers due to the planar nature of the carbocation intermediate.**Additional Information:**This reaction is a classic example of an SN1 mechanism, where the rate-determining step involves the formation of a carbocation intermediate. The use of ethanol not only acts as a nucleophile but also as a solvent, stabilizing the charged species in the reaction pathway.(Note: The platform interface includes an "Upload" button for users to upload their files, presumably related to exercises or responses for further analysis or grading.)

This reaction follows SN1 mechanism, In SN1 mechanism firstly leaves group leaves and carbocation generated then through rearrangement the stable carbonation is formed then nucleophile attacks on the carbonation to form an enantiomer.Mechanism of the reaction is: Step 1: First leaving group leave. Step 2: 1,2-Hydride shift for stable carbonation. Then nucleophile attacks on the carbocation. These two products are enantiomers.