proportion of males among patients discharged from Pennsylvania follows: Is the number (1.96) If not, how do you get it? Thank you! Please explain! a constant?

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bartleby
Fundamentals of Biostatistics
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Chapter 6, Problem 17P
To determine
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Find a 95% confidence interval for the percentage of males among patients discharged from Pennsylvania
hospitals.
Answer to Problem 17P
ASK AN EXPERT CHAT VX MATH SOLVER
-
The 95% confidence interval for the percentage of males among patients discharged from Pennsylvania
hospitals is (0.25, 0.63).
Explanation of Solution
From Exercise 15, the best point estimate for the percentage of males among patients discharged from
Pennsylvania hospitals,p is 0.44.
From Exercise 15, the standard error of the sample proportion is 0.099.
Since the required confidence interval is 95%, the two-tailed z-critical value is 1.96.
The 95% confidence interval for the proportion of males among patients discharged from Pennsylvania
hospitals is given and calculated as follows:
CI = ô ± z.q (SE)
0.44 ± (1.96) (0.099)
0.44 0.19404
= (0.24596, 0.63404)
≈ (0.25, 0.63)
Is the number (1.96)
If not, how do
Thank you!
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Chapter 6, Problem 16P
BB
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Chapter 6, Problem 18P
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Thus, the 95% confidence interval for the percentage of males among patients discharged from Pennsylvania
hospitals is (0.25, 0.63).
O
(1.96) a constant?
you get it?
Please explain!
Transcribed Image Text:bartleby Fundamentals of Biostatistics Question Q SEARCH Chapter 6, Problem 17P To determine Expert Solution & Answer Find a 95% confidence interval for the percentage of males among patients discharged from Pennsylvania hospitals. Answer to Problem 17P ASK AN EXPERT CHAT VX MATH SOLVER - The 95% confidence interval for the percentage of males among patients discharged from Pennsylvania hospitals is (0.25, 0.63). Explanation of Solution From Exercise 15, the best point estimate for the percentage of males among patients discharged from Pennsylvania hospitals,p is 0.44. From Exercise 15, the standard error of the sample proportion is 0.099. Since the required confidence interval is 95%, the two-tailed z-critical value is 1.96. The 95% confidence interval for the proportion of males among patients discharged from Pennsylvania hospitals is given and calculated as follows: CI = ô ± z.q (SE) 0.44 ± (1.96) (0.099) 0.44 0.19404 = (0.24596, 0.63404) ≈ (0.25, 0.63) Is the number (1.96) If not, how do Thank you! < Previous Chapter 6, Problem 16P BB Next > Chapter 6, Problem 18P SAVE DATE THIS SOLUTION Thus, the 95% confidence interval for the percentage of males among patients discharged from Pennsylvania hospitals is (0.25, 0.63). O (1.96) a constant? you get it? Please explain!
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Given that 

Confidence Level = 95%

 

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