Situation 1: A-DA W14X120 is used as a tension member in atruss. The flanges of the member are connected to a gusset plate by ¾ inch boltasshown below. Use A36 steel with Fy=36 ksi and Fu=58 ksiProperties and DimensionAg=35.30 in^2rx = 6.24 inry = 3.74 ind=14.5 intf=0.94 inbf=14.7 intw=0.59 inYk1=1.5k=1.54I tf=0.94d=14.5tw=0.59bf=14.7A. Determine the Yielding Capacity of the section based on LRFD (kips)Round your answer to 2 decimal places.From Situation 1:b. Determine the effective net area of the section. For shear lag Factor U used the recommended values depending on thedimension of the section for W shapes with 3 or more fasteners per line. Note: use hole diameterif bf <d;U=0.85 else U =0.93Round your answer to 3 decimal places.From Situation 1:c. Determine the Tensile Rupture capacity of the section based on LRFDFrom Situation 1:d. Determine the Demand to Governing Capacity Ratio (based on yielding and rupture only) if the Demand load carried by thesection are DL=200 kips LL=400 kips use LRFDRound your answer to 3 decimal places.

a W14 x 120 is used as the tension member in a truss .The flanges of the member are connected to a…

Answered: Properties and Dimension Ag=35.30 in^2…

Properties and Dimension Ag=35.30 in^2 X = 6.24 in ry = 3.74 in d=14.5 in tf=0.94 in bf=14.7 in tw=0.59 in Y k1=1.5 I tf=0.94 1.54 -tw=0.59 bf=14.7

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Related questions

Q: Q5/ The axial force applied on the beam is :equal to 10 kN he100 mm 2m 4m b-50 mm Non of these 10 KN…

A: Find the axial force on th beam.

Q: Consider a suspension settling under hindered settling conditions (type III) in a cylinder with…

A: To find:(a) The hindered velocity of settling.(b) The Galileo number and The Richardson Zaki…

Q: 4 A water Pipe is to beconstructed with a 207, grade in the novth divection and a 10% grade in the…

A: Hello. Since you have posted multiple questions and not specified which question needs to be solved,…

Q: Considering Figure 20-8 (textbook), the torsion geometry parameter, Jw, for case 4 when b-6 and d=9…

A: b=6d=9

Q: A shaft of diameter 25-0.04 mm is assembled in a hole of diameter 25+0.02 mm. -0.00 Match the…

A: Calculating allowance, maximum clearance and maximum material limit for the hole.

Q: 3 E=20000MPa I=1.61x10^6 sqmm Analyze the structure using Consistent Deformation Method. Draw Shear…

Q: 50 h = Poot = wd+ √₂-50 ft T only unknown 50 рзід 17 water glycerin 5.g=1.26 Jg=1.26 d Local gage =…

Q: Lisht pole given bolow Lomp Wind speedezo0Luch feefur of salfety= 45 WL=200ky.g If the pole is o…

A: given; ⇒load(wL)=200kg*g =200*9.81 =1962N⇒distance from support to…

Q: 750-10UNC-24 100 0.600 4.3875 THRU 2776-2 CRS M BAM 756 -178- 1-8UNC-2A 1.25 LG GENERA S Rockwell…

A: I have attached the image below Explanation:

Q: Q.1 Find px – Py. Yx = 8650 N / m³ YA = 135000 N / m³ YB = 7800 N / m³ Yc = 9700N / m³ Yy = 12 N /…

Q: 11 * FIRE Is I0kG XND CONNECTED To AN AXLE SHAFT IS ROT&TED s RETARDED , FF THE NATURAL FREQUENCY is…

Q: An aircraft engine develops 150kW at 1500rpm. The engine output shaft is steel which fails when the…

Q: Data Table 1 y= 1m d= 5cm M=150g

Q: Problem 3 Arm- N=24 P C N=42 -N-18 -H N18 No 20 -NG -40 N18 N₁ = 18 Ne=24 Nc-40 A is driven cw@…

A: Given data as per question speed of A gear =1066.6 rpm (clockwise)

Q: w(x) = 24VX N/m %3D 96 N/m A B 370 What is the resultant force of the distributed load?

Q: 2. For the linkage shown in Fig. 2, determine VB and 0₁. 0₂04 = 4 in. auquo oda to anoblsoq ulugas i…

Q: Solu for gap {d). Given: 11- 198.15 K T2= 315.15 K Steel irils e 40 mm Sterl rails lincar expansion…

Q: 90. A pump propels a water flow of 222 l/s through the given horizontal piping system to a closed…

A: Given:Water flow rate, Q=222 L/s=222*10-3 m3/s=0.222 m3/sLiquid level in the closed tank, zC=3…

Q: Property Density Yield Strength Ultimate Tensile Strength Poisson Ratio Shear Modulus ASTM A710…

Q: 24. Find F12 for the cone shown in the figure. Use R = 0.5 m and L, = 1.5 m. Surface A2 has the same…

Q: !!!slides[5]!!! The pin at C has a diameter of 44 mm. Assume that the pin at C is supported in a…

Q: 2) = 20KN S=3 Sy = 960 lPa Bobt joint mthoud clearance Findi d

A: Given data: P=20 kNs=3Sy=460 MPa Need to determine the diameter of the rivet.

Q: Q4: A cantilever beam of carbon steel is subjected to a load P varying from -50 to 150 N. Determine…

A: When external load on a component is not static, but varying in magnitude with respect to time, such…

Q: A shaft is supported by two ball bearings at the ends, as shown in Figure Q3. C Gear R1 R2 Figure Q3…

Q: Find ly

A: To find the length ly, we need to use the Pythagorean theorem. Let's break down the problem and…

Q: PROBLEM 3: The coefficients of friction between the block and the rail are µ, and µg. Determine the…

Q: The following parameters are given for the journal bearing. u = 4 preyn, N = 643 rev/min, W = 843…

A: Given Data in this problem is :⇒Viscosity of the fluid μ = 4 μreyn = 4×10-6 lb-sin2⇒Journal…

Q: #2) =Fcos x = F Sin By Fy= Fsin Ox= Fuos by angles 14k lok F RK K 12k 15k Find Re 7k b 16

A: As per our guidelines, we are supposed to answer only first one question in case of multiple…

Q: (3) P = 0.0400 T= 28.98 x = 0.913 H= 2342.64 H*= -204.85 M = 103.5 (9) P= 1.0135 T= 22 Sub = 78.0 H…

A: Hello. Since your question has multiple sub-parts, we will solve first three sub-parts for you. If…

Q: truss

A: the truss using both the force method and the stiffness method. Here's a breakdown of the steps…

Q: 1) Convert 20 hp to KN 2 Free Body diagram. 3 to all link Force Analysis to all Link

A: (1) hp means horsepower and hp is the unit of power while kN (kilo Newton ) is the unit of force. so…

Q: 0, = 100MPa %3D 300MPA = 400MPa Ox

Q: L = 3 m Lotfen birini seçin: a 98.48 mm D. 120.04 mm C 150.92 mm d. 175.14 mm . 142.02 mm

Q: find shear force x’y’ and derívate the equation for tau x’y’

A: To find:Shear force and shear stress on an inclined plane.

Q: Sample Numerical Problem • Link 2: m2 = 0.0052 kg - ICAR = 0.05 kgm2 e, = 60° a, = -10 rad/s? a CM2…

A: Given Data **As in given statement there is not demanding of question but we had given the value of…

Q: QU The journal speed of a 100mm diameter journal is 2500 rpm. The journal is supported by a short…

A: Given radial load, journal speed, diameter, bearing length clearance ratio,the operating…

Q: Compute radius of mohr circle

A: Given data : Normal stress in X direction σX=300 MPa Normal stress in Y direction σY=-200 MPa Shear…

Concept explainers

Hydronics

Question

Situation 1: A-D
A W14X120 is used as a tension member in atruss. The flanges of the member are connected to a gusset plate by ¾ inch boltas
shown below. Use A36 steel with Fy=36 ksi and Fu=58 ksi
Properties and Dimension
Ag=35.30 in^2
rx = 6.24 in
ry = 3.74 in
d=14.5 in
tf=0.94 in
bf=14.7 in
tw=0.59 in
Y
k1=1.5
k=1.54
I tf=0.94
d=14.5
tw=0.59
bf=14.7
A. Determine the Yielding Capacity of the section based on LRFD (kips)
Round your answer to 2 decimal places.
From Situation 1:
b. Determine the effective net area of the section. For shear lag Factor U used the recommended values depending on the
dimension of the section for W shapes with 3 or more fasteners per line. Note: use hole diameter
if bf <
d;U=0.85 else U =0.9
3
Round your answer to 3 decimal places.
From Situation 1:
c. Determine the Tensile Rupture capacity of the section based on LRFD
From Situation 1:
d. Determine the Demand to Governing Capacity Ratio (based on yielding and rupture only) if the Demand load carried by the
section are DL=200 kips LL=400 kips use LRFD
Round your answer to 3 decimal places.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step 3

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 3 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.

Similar questions

The beam dimensions in Figure 1 are a = 4in, d = 7.5in, l = 10in, b = 0.1in, h = 1in, and r = 0.167 in. The material is steel (E = 30 ×106 psi). The supporting wall is much stiffer than the beam. At the notch, the stress concentration factor is K = 1.56. F = 50 lbf A) Find the normal stress values at point D and the notch B) Find the Von mises stress for the entire beam
Frid the potential enegy m = 33kg h = 10m g=lomis?
10Ocm IS 60 I5 20 20, 20, 10 20 G=? IGX =?
6 Assuming that the wind force reverses in direction, the maximum service load based on a combined mechanism with a plastic hinge at E. 1.4P P. Lengths: AB = 6.3m F BE = 3.9m M, EF = 1.8m 1.3M, FC = 4.5m %3D 1.5M, CD 5.1m %3D Assume Fw = 0.8P Section BC W30x90
No Handwriting please
3
Radius of mohr circle
lock Page 7 of 8 Problem 6 4.0 kN 1.5 kN/m |A 1.0 m→1.0 m→* 2.0 m- For the beam shown above look at the location 1.1 meter to the right from the point A. Goal 1 (3 points) define formula to estimate shear force at the location of interest Goal 2 (2 points) calculate the value of shear force at the location of interest. Goal 3 (3 points) define formula for bending moment at the location of interest Goal 4 (2 points) calculate the value of bending moment for the location of interest.
HW #3 04/12/2020 due date. wednesden Tx=/25 MPa T2=? uncler Novolume cheye! do 10cm 20=0 ( For novalmachaye Sscm Socm N: 0.4 E= 10 k 125-10040z=0 102= -25 MPa Fz=? Az 0.2m X0.3m %3D Q: Ex=? final dianeter. F2 -25M x (200 mx 300) t2= -1500000N~/500KN
For the beam illustrated in the figure, find the locations and magnitudes of the maximum tensile bending stress due to Mand the maximum shear stress due to V. Parameters are a= 320 mm, b=140 mm, c= 21 mm, h= 38 mm, and F= 4400 N. ܝ ܝ amm The moment of inertia is Cmm mm 96, x105,mm4. .Pa 5572 ܓ | The maximum tensile bencing stress due to Mis The maximum shear stress due to Vis 2.58 MPa.
T2 = 390 K Vz = ? P, = 300 kPa = 400 K v, = 20 m/sec D1 = 15 cm P1 = ? T1 m =?
Beam 10: Beam is W 10 X 77: The 65 plf is in addition to beam weight!!!! 2500 lbs. Resisting MRI Moment R1 3₁ 65 plf +17 ECL : 142x21 - 2982 = 12'-0" 2 F 17 = 142 9'-0" 21-0' RI MRI =