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Consider a suspension settling under hindered settling conditions (type III) in a cylinder with radius 50 mm. Suspension properties are listed in the table below. Property Fluid density (g/cm³) Fluid dynamic viscosity (CP) Particle density (g/cm³) Value 0.867 14.3 1.45

Consider a suspension settling under hindered settling conditions (type III) in a cylinder with radius 50 mm. Suspension properties are listed in the table below. Property Fluid density (g/cm³) Fluid dynamic viscosity (CP) Particle density (g/cm³) Value 0.867 14.3 1.45

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
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answers = 

(a) 1.6 x 10-5 m/s (b) Ga = 3.35 x 109 , n = 4.66

 

eqn sheet attached. show wokring to reach answers please

Consider a suspension settling under hindered settling conditions (type III) in a cylinder with radius 50 mm. Suspension properties are listed in the table below. Property Fluid density (g/cm³) Fluid dynamic viscosity (CP) Particle density (g/cm³) Particle mean diameter (µm) Porosity (a) Determine the hindered velocity of settling. (b) A new suspension is settling under hindered settling conditions (type III) in a cylinder with radius 120 mm. Suspension properties are listed in the table below. Property Fluid density (g/cm³) Fluid dynamic viscosity (CP) Particle density (g/cm³) Particle mean diameter (um) 0.2 < Re < 1 In this case, the single particle velocity 1.7 x 10-4 m/s. Determine the Galileo number and the Richardson Zaki index selecting the appropriate Richardson Zakin index equation. Re at terminal velocity Re < 0.2 1 < Re < 500 500 < Re n = 4.65 + 19.5 Richardson Zaki n index (5) Value 0.867 14.3 1.45 55 0.55 n = 4.35 + 17.5 n = Value 0.864 5.5 2.1 100 - 17.5 (1)) Re 4.45 + 18 2.39 Re-0.03 Re-0.1
Transcribed Image Text:Consider a suspension settling under hindered settling conditions (type III) in a cylinder with radius 50 mm. Suspension properties are listed in the table below. Property Fluid density (g/cm³) Fluid dynamic viscosity (CP) Particle density (g/cm³) Particle mean diameter (µm) Porosity (a) Determine the hindered velocity of settling. (b) A new suspension is settling under hindered settling conditions (type III) in a cylinder with radius 120 mm. Suspension properties are listed in the table below. Property Fluid density (g/cm³) Fluid dynamic viscosity (CP) Particle density (g/cm³) Particle mean diameter (um) 0.2 < Re < 1 In this case, the single particle velocity 1.7 x 10-4 m/s. Determine the Galileo number and the Richardson Zaki index selecting the appropriate Richardson Zakin index equation. Re at terminal velocity Re < 0.2 1 < Re < 500 500 < Re n = 4.65 + 19.5 Richardson Zaki n index (5) Value 0.867 14.3 1.45 55 0.55 n = 4.35 + 17.5 n = Value 0.864 5.5 2.1 100 - 17.5 (1)) Re 4.45 + 18 2.39 Re-0.03 Re-0.1
Dimensionless spray flux: Critical velocity: Archimedes number: F (when Ar> 80): F (when Ar < 80): Galileo number: Ga = Unhindered settling, single particle velocity: V = Hindered settling velocity: = εn Vs D³gp μ² Richardson and Zaki index: Brownian distance: L = Brownian time: t = 4.8-n n-2.4 2kT 3πxμ 3Q 2VsWsdd Vc = F√gD (2-1) Ar = x³ pr(Ps - Pf) 3 t Va = Turbulent regime equation: F = a Arb F = √2 [2 +0.3 log10 ( 216kTμ лg² (Ps-Pf)²x5 x Vs Pf Particle Reynold's number: Re = fl - 1 Reynold's number in a packed bed: Re = = 0.043 Ga 0.57 -ΔΡ 32μU D² Hagen-Poiseuille equation: - 1 Carman-Kozeny equation:=kμUS² xUpf μ(1-ε) (18)² 83 g(Ps-Pf)x² 18μ (DD)] = 1.75 PfU² (1-8) x 83 [1-1.24 24 (1) 0:²7]
Transcribed Image Text:Dimensionless spray flux: Critical velocity: Archimedes number: F (when Ar> 80): F (when Ar < 80): Galileo number: Ga = Unhindered settling, single particle velocity: V = Hindered settling velocity: = εn Vs D³gp μ² Richardson and Zaki index: Brownian distance: L = Brownian time: t = 4.8-n n-2.4 2kT 3πxμ 3Q 2VsWsdd Vc = F√gD (2-1) Ar = x³ pr(Ps - Pf) 3 t Va = Turbulent regime equation: F = a Arb F = √2 [2 +0.3 log10 ( 216kTμ лg² (Ps-Pf)²x5 x Vs Pf Particle Reynold's number: Re = fl - 1 Reynold's number in a packed bed: Re = = 0.043 Ga 0.57 -ΔΡ 32μU D² Hagen-Poiseuille equation: - 1 Carman-Kozeny equation:=kμUS² xUpf μ(1-ε) (18)² 83 g(Ps-Pf)x² 18μ (DD)] = 1.75 PfU² (1-8) x 83 [1-1.24 24 (1) 0:²7]
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