Professor Pan came up with the following hypotheses. Which of the following null or alternative hypotheses is correct? Ha: μ 1-μ 2 > 0 Ho: μ 1-μ2>0 Ho: u 1-2-0 none of the above- Ha: μ 1-μ 2 <0
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- Please answer part d(a) Find the P - value for the test statistic z=1.31 for the following null and alternative hypotheses:Ho: The population mean is 16.Ha: The population mean is less than 16.The P - value is (b) Find the P - value for the test statistic z=1.31 for the following null and alternative hypotheses:Ho: The population mean is 16.Ha: The population mean is not equal to 16.The P - value is4) In the following null and alternative hypotheses Họ : u =68 and H A : µ± 68 , a =0.02 , xr = 69.02 , o = 5.4 and n=40 a. State the decision rule in terms of the critical value of the test statistic. b. State the calculated value of the test statistic. c. State the conclusion. d. Compute the p - value. Does its value support the claimed obtained in part a justify.
- In testing the hypotheses H0: p = 0.5 vs Ha: p <= 0.5, suppose you get a p-value 0.022. Thenyou realize that the one sided alternative is too restrictive and re-do the test with a two sidedalternative Ha : p =/= 0.5.Based on the new p-value, what will be your conclusion ? A. Reject H0 at alpha = 0.01 but not at alpha = 0.05; 0.1.B. Reject H0 at alpha = 0.05 and alpha = 0.1 but not at alpha = 0.01.C. Fail to reject H0 at all the above alpha values.D. Reject H0 at alpha = 0.05 and alpha = 0.01 but not at alpha = 0.1.E. Reject H0 at all the above alpha values.A Moving to another question will save this response. Question 15 Consider the Hypotheses Ho: u = 36 vs H1:u > 36. Assume X-37, o =4 and n-64 a) Using a=0.025 , find the critical value(s). Type the critical values(s) b) Find the test statistic. (Type this number) )At a=0.025, is Ho accepted or not accepted? (Type accepted or not accepted) A Moving to another question will save this responseConsider the following null Hypothesis: Ho: µ-30 Given a sample of n=16 and with x =29.4, s=0.5 and a=0.05 Solution: 1- What is the alternative hypothesis H₁: 2- What kind of test you are going to use? 3- Calculate tx= Q3 х-мно S √√n 4- Calculate: a/2 = Calculate df= = (From table-5 two tail) ta/2= 5- Check the answer: ()|tx|to/2 6- Check your conclusion: () Reject Ho () Don't Reject Ho
- 2. A new insecticide is advertised to kill more than 95% roaches upon contact. In a laboratory test, the insecticide was applied to 400 roaches and 384 died immediately after contact. Is this sufficient evidence to support the advertised claim? Use α=0.05. (d) Conclusion for the problem above is Do not reject the null hypothesis and new insecticide does not kill more than 95% of roaches upon contact. O Reject the null hypothesis and new insecticide kills more than 95% of roaches upon contact. Reject the null hypothesis and new insecticide does not kill more than 95% of roaches upon contact. Do not reject the null hypothesis and new insecticide kills more than 95% of roaches upon contact.Question 6 and 7A tax accountant would like to test the claim that the proportion of individuals who owe when filing their taxes is greater than 0.20. If the z− test statistic was calculated as z=1.94, does the tax accountant have enough evidence to reject the null hypothesis? Assume α=0.05.
- The recidivism rate for convicted sex offenders is 13%. A warden suspects that this percent is lower if the sex offender is also a drug addict. Of the 371 convicted sex offenders who were also drug addicts, 45 of them became repeat offenders. What can be concluded at the αα= 0.01 level of significance?For this study, we should use The null and alternative hypotheses would be: Ho: (please enter a decimal) H1: (Please enter a decimal)The test statistic = (please show your answer to 3 decimal places.)The p-value = (Please show your answer to 4 decimal places.)The p-value is ααBased on this, we should the null hypothesis.Thus, the final conclusion is that ... The data suggest the population proportion is not significantly lower than 13% at αα= 0.01, so there is statistically insignificant evidence to conclude that the population proportion of convicted sex offender drug addicts who become repeat offenders is lower than 13%.The data suggest the population proportion is not significantly…Only 19% of registered voters voted in the last election. Will voter participation increase for the upcoming election? Of the 363 randomly selected registered voters surveyed, 91 of them will vote in the upcoming election. What can be concluded at the αα = 0.01 level of significance? For this study, we should use The null and alternative hypotheses would be: H0:H0: _______ (please enter a decimal) H1:H1: ________ (Please enter a decimal)known standard deviation