When the following hypotheses are being tested at 5%level with o knownНо: и2 11H1: µ <11the null hypothesis will be rejected if the test statisticZ isА.< -1.645В.> 1.645C. > 1.96 or, < -1.96D. > 2

Given: Null and Alternative hypotheses H0: μ≥11H1: μ<11 Population Standard Deviation σ known The…

Answered: When the following hypotheses are being…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Suppose you want to test the claim that u, #H2. Two samples are randomly selected from each population. The sample statistics are given below. At a level of significance of a = 0.05, when should you reject Ho? n, = 50, n2 = 60, x, = 29, x2 = 27, o, = 1.5, o2 = 1.9 O A. Reject H, if the standardized test statistic is less than - 1.96 or greater than 1.96. O B. Reject H, if the standardized test statistic is less than - 2.33 or greater than 2.33. O C. Reject H, if the standardized test statistic is less than -2.575 or greater than 2.575. O D. Reject H, if the standardized test statistic is less than - 1.645 or greater than 1.645.
Researchers were interested in determining whether there was a difference in crime rates in areas where there is high youth unemployment vs low youth unemployment. Alpha (level of significance) was set at .05. 1.) State the null and alternate hypotheses
A random sample of 46 adult coyotes from Northern Minnesota showed the average age to be sample mean of 2.05 years. The population standard deviation is known to be o = 1.13 years. However, it is thought that the average age of coyotes is u = 1.75 years. Test to see if the coyotes in Northern Minnesota live longer than the national average of 1.75 years. Use 0.03 level of significance. What are the hypotheses? A: Ho µ= 1.75 years vs HA µ> 1.75 years B: Ho µ= 1.75 years vs HA H 2.05 years D: Ho µ = 2.05 years vs HA u< 2.05 years O A D O O
A sample mean, sample standard deviation, and sample size are given. Perform the required hypothesis test about the mean, μ, of the normal population from which the sample was drawn. H0: μ = 132, Ha: μ ≠ 132, x=137 , s = 14.2, n = 20, α = 0.10 P-value = 0.0582. Reject H0. There is sufficient evidence to conclude that the mean is different from 132. P-value = 0.0659. Reject H0. There is sufficient evidence to conclude that the mean is different from 132. P-value = 0.1318. Do not reject H0. There is not sufficient evidence to conclude that the mean is different from 132. P-value = 0.1164. Do not reject H0. There is not sufficient evidence to conclude that the mean is different from 132.
Suppose are running a study/poll about the proportion of women over 40 who regularly have mammograms. You randomly sample 117 people and find that 92 of them match the condition you are testing.Suppose you are have the following null and alternative hypotheses for a test you are running:H0:p=0.83Ha:p<0.83Calculate the test statistic, rounded to 3 decimal places z=z=
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If chi-square is NOT statistically significant with a sample size of 100 and sample size is increased to 1,000, the new chi-square: a. will have the same likelihood of being statistically significant than the previous chi-square b. cannot tell until the new chi-square is calculated c. will be less likely to be statistically significant d. will be more likely to be statistically signficant
Previously, 12.1% of workers had a travel time to work of more than 60 minutes. An urban economist believes that the percentage has increased since then. She randomly selects 80 workers and finds that 18 of them have a travel time to work that is more than 60 minutes. Test the economist's belief at the x = 0.1 level of significance. What are the null and alternative hypotheses? P = 0.121 versus H1: p Ho: p (Type integers or decimals. Do not round.) > 0.121 Because npo (1- Po) = < 10, the normal model may not be used to approximate the P-value. (Round to one decimal place as needed.)
Assume the critical value on the right side of a Z distribution was 1.96. A researcher received a sample mean that he translated into a z score of 2.5. What decision should the researcher make regarding the null hypothesis?
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Westjet claims that it's avearage time to fly to Toronto from Thunder Bay is 121 minutes. A random sample of 29 flights from Thunder Bay to Toronto were observed and yeilded a mean of 140 minutes. Assuming that o = 3.1 do we have enough evidence to show that the mean flight is more than 121 minutes? Use a = 0.1 and use our tables. Select the correct null and alternative hypotheses: OA. Ho: X= 140,HA: X 121 OF. Ho X = 140,H₁ : X > 140 OG. None of the above Select the type of distribution to be used in this question: OA. Z-distribution B. t-distribution OC. Chi-Square distribution OD. None of the above The rejection region for this test is: OA. (-∞, -1.28) OB. (1.96,∞) OC. (1.645, ∞) OD. (1.28, ∞) OE. (-∞, -1.96) OF. (-∞, -1.645) OG. (-∞, -1.96) U (1.96,∞) OH. (-∞, -1.28) U (1.28,00) OI. (-∞, -1.645) U (1.645, ∞) OJ. None of the above Test statistic = The conclusion for this test is: OA. Fail to Reject Ho OB. Reject Ho OC. Fail to Reject HA OD. Reject HA OE. None of the above

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When the following hypotheses are being tested at 5% level with o known Ho: µ 2 11 H1:H <11 the null hypothesis will be rejected if the test statistic Z is A. <-1.645 B. > 1.645 C. > 1.96 or, < -1.96 D. > 2