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Production target : 60 wt% nitric acid at 280 ton/day Raw material : Ammonia, Water, Oxygen from air (1mol basis dry air : 0.78 N2, 0.21 O2,0.01 Ar) Select the total mass balance and elemental balances of hydrogen and nitrogen to obtain f35, f42, and f43. (The amount of out tail gas is 28.679kg)

Production target : 60 wt% nitric acid at 280 ton/day Raw material : Ammonia, Water, Oxygen from air (1mol basis dry air : 0.78 N2, 0.21 O2,0.01 Ar) Select the total mass balance and elemental balances of hydrogen and nitrogen to obtain f35, f42, and f43. (The amount of out tail gas is 28.679kg)

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Production target : 60 wt% nitric acid at 280 ton/day

Raw material : Ammonia, Water, Oxygen from air (1mol basis dry air : 0.78 N2, 0.21 O2,0.01 Ar)

Select the total mass balance and elemental balances of hydrogen and nitrogen to obtain f35, f42, and f43.

(The amount of out tail gas is 28.679kg)

Air 36 000 kg Ammonia 2006 kg Make-up water ?kg 1 2 3 PROCESS Basis: 1 hour 4, 5, Tail gas ? kg Product nitric acid 11 667 kg (i.e. 7000 kg HNO3 + 4667 kg H₂O)
Transcribed Image Text:Air 36 000 kg Ammonia 2006 kg Make-up water ?kg 1 2 3 PROCESS Basis: 1 hour 4, 5, Tail gas ? kg Product nitric acid 11 667 kg (i.e. 7000 kg HNO3 + 4667 kg H₂O)
Component i formula 1 NH3 2 N2 3 02 4 Inert 5 H₂O 6 NO2 7 HNO3 Total Mi g/mol 17.30 28.10 32.00 39.95 18.02 46.01 63.10 1 £12 f13 f14 f15 Stream j 2 3 2006 36000 2006 4 f42 f43 f44 f35 f45 f46 5 4667 7000 11667
Transcribed Image Text:Component i formula 1 NH3 2 N2 3 02 4 Inert 5 H₂O 6 NO2 7 HNO3 Total Mi g/mol 17.30 28.10 32.00 39.95 18.02 46.01 63.10 1 £12 f13 f14 f15 Stream j 2 3 2006 36000 2006 4 f42 f43 f44 f35 f45 f46 5 4667 7000 11667
Expert Solution
Step 1

Given,

The mass of air is 36000 kg.

The mole% of air is 78% N2, 21% O2 and 1%Ar. Here Ar acts as Inert gas.

The molar masses of N2, O2, and Ar are 28.10 g/mol, 32 g/mol, and 39.95 g/mol respectively.

 

The mass of Air, m1 = 36000 kg

The mass of ammonia, m2 = 2006 kg

The mass of make-up water, m3 = f35

The mass of Tail gas, m4 = 28679 kg

The mass of Nitric acid, m5 = 11667 kg

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