Compute the upper and lower control limits if samples of size 16 are to be used.UCL =LCL =Construct the x chart for this process.16.516.5-16.516.516.0-16.0-16.0-16.0-15.515.5-UCL15.515.5-UCLUCL15.0UCL15.015.015.014.514.514.514.514.0-14.014.014.0-LCLLCL13.513.5LCL13.5-13.5LCL13.0+13.013.0+13.0-24610246.810246810246810Sample NumberSample NumberSample NumberSample Number(c) What happens to the limits of the control chart as the sample size is increased? Discuss why this is reasonable.The limits become ---Select---as n increases. If the process is in control, the larger samples should have --Select-- vvariance and should fall ---Select--- vu = 14.5.Sample Mean XSample Mean XSample Mean XSample Mean X A process that is in control has a mean of u = 14.5 and a standard deviation of o = 0.6.(a) Compute the upper and lower control limits if samples of size 4 are to be used.UCL =LCL =Construct the x chart for this process.17.0f16.516.0-15.515.014.514.013.517.0-16.516.0-15.515.017.0-16.5-* 16.0-15.515.017.0-16.5-* 16.0UCLUCLUCL15.515.0UCL14.514.013.5-* 13.012.514.514.013.513.014.514.013.5-* 13.0LCLLCLLCL13.0-12.5+LCL12.5-12.56 8481021024681024 6 810eticatheerttheSample NumberSample NumberSample NumberSample Number(b) Compute the upper and lower control limits if samples of size 8 are to be used. (Round your answers to three decimal places.)UCL =LCL =Construct the x chart for this process.16.5+16.0-16.5-16.516.516.0-16.0-16.0-UCLUCLUCL15.515.515.515.5UCL15.015.0-15.015.014.514.514.514.514.0-14.0-14.0-14.013.513.513.513,5-LCLLCLLCLLCL13.0-13.013.013.0-6 86 86 82410210468.102410Sample NumberSample NumberSample NumberSample NumberCompute the upper and lower control limits if samples of size 16 are to be used.UCL =LCL =Sample Mean XSample Mean XSample Mean XSample Mean xSample Mean XSample Mean XSample Mean XSample Mean X

The X -bar chart is a type of SHEWART control chart that is used to monitor the arithmetic means…

process that is in control has a mean of u = 14.5 and a standard deviation of o = 0.6. (a) Compute the upper and lower control limits if samples of size 4 are to be used. UCL - LCL - Construct the x chart for this process. 17.0 16.5 17.0 16.5 * 16.0 15.5 15.0 14.5 14.0 13.5 13.0 12.5 17.0 16.5 * 16.0- 15.5 15.0 14.5 17.0 16.5 * 16.0 E 15.5- UCL 16.0 15.5 15.0 UCL. UCL UCL 14.5 14.0 13.5 i 13.0 12.5 14.0 13.5 13.0 12.5 15.0 14.5 214.0- 13.5 A 13.0- 12.5 LCL LCL LCL. LCL 4 8. 10 4 10 2 8 10 2 6 10 Sample Number Sample Number Sample Number Sample Number (b) Compute the upper and lower control limits if samples of size 8 are to be used. (Round your answers to three decimal places.) UCL - LCL - Construct the x chart for this process. 16.5 16.0- 16.5 16.0- 16.5 16.0- 15.5 16.5 16.0 UCL UCL UCL 15.5 15.5 15.5 UCL. 15.0 15.0 15.0 15.0 14.5 14.0 13.5 13.0 14.5 14.5 14.5 14.0 14.0 14.0 13.5 13.0 13.5 13.5 LCL LCL LCL LCL. 13.0- 13.0 2 4 6. 10 2 4 6 10 4 8 10 10 Sample Number Sample Number Sample Number Sample Number Compute the upper and lower control limits if samples of size 16 are to be used. UCL - Sample Mean x Sample Mean X Sample Mean X Sample Mean X Sample Mean X Sample Mean X Sample Mean X

process that is in control has a mean of u = 14.5 and a standard deviation of o = 0.6. (a) Compute the upper and lower control limits if samples of size 4 are to be used. UCL - LCL - Construct the x chart for this process. 17.0 16.5 17.0 16.5 * 16.0 15.5 15.0 14.5 14.0 13.5 13.0 12.5 17.0 16.5 * 16.0- 15.5 15.0 14.5 17.0 16.5 * 16.0 E 15.5- UCL 16.0 15.5 15.0 UCL. UCL UCL 14.5 14.0 13.5 i 13.0 12.5 14.0 13.5 13.0 12.5 15.0 14.5 214.0- 13.5 A 13.0- 12.5 LCL LCL LCL. LCL 4 8. 10 4 10 2 8 10 2 6 10 Sample Number Sample Number Sample Number Sample Number (b) Compute the upper and lower control limits if samples of size 8 are to be used. (Round your answers to three decimal places.) UCL - LCL - Construct the x chart for this process. 16.5 16.0- 16.5 16.0- 16.5 16.0- 15.5 16.5 16.0 UCL UCL UCL 15.5 15.5 15.5 UCL. 15.0 15.0 15.0 15.0 14.5 14.0 13.5 13.0 14.5 14.5 14.5 14.0 14.0 14.0 13.5 13.0 13.5 13.5 LCL LCL LCL LCL. 13.0- 13.0 2 4 6. 10 2 4 6 10 4 8 10 10 Sample Number Sample Number Sample Number Sample Number Compute the upper and lower control limits if samples of size 16 are to be used. UCL - Sample Mean x Sample Mean X Sample Mean X Sample Mean X Sample Mean X Sample Mean X Sample Mean X

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Times for a surgical procedure are normally distributed. There are two methods. Method A has a mean of 31 minutes and a standard deviation of 2 minutes, while method B has a mean of 35 minutes and a standard deviation of 1.0 minutes. (a) Which procedure is preferred if the procedure must be completed within 30 minutes? O Method A O Method B O Either Method (b) Which procedure is preferred if the procedure must be completed within 38.0 minutes? O Either Method O Method A O Method B (c) Which procedure is preferred if the procedure must be completed within 37 minutes? O Method B O Either Method O Method A < Prev 19 of 19 Next to search 22 立

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* Question Completion Status: OC. 0.0099 d. 0.0918 QUESTION 3 EPA fuel economy estimates for automobile models tested recently predicts a mean of 24 mpg and a standard deviation of 6 mpg. Assume that a Normal model applies, N(24, 6 ). What mpg for the automobiles would be the cutoff value for the lowest 10% of the mpg's (the 10th percentile of gas mileage)? O a. 12.80 mpg O b. 10.00 mpg O c. 31.38 mpg O d. 16.32 mpg QUESTION 4
This assignment is worth 1 points. The extra point will be added to your overall course grade. For example: if you receive an 88% in the course you can receive up to 1 point giving you a new score of 89%. The following rubric will be used. 0.25 point for drawing the normal distribution curve with the mean value labeled on the curve and the appropriate area shaded. 0.25 point for determining the value of the standard deviation of the sample mean. 0.5 point for finding the correct probability. All work must be shown in order to receive any credit. Please upload your completed assignment here. The length of time taken on the SAT for a group of students is normally distributed with a mean of 2.5 hours and a standard deviation of 0.25 hours. A sample size of n = 60 is drawn randomly from the population. Find the probability that the sample mean is between two hours and three hours.
please interpet seperately. there are tw coountries
How do you find (b.)?
10) A county is considering raising the speed limit on a road because they claim that the mean speed of vehicles is greater than 40 mi/hr. A random sample of 15 vehicles has a mean speed of 43 mil/hr and a standard deviation of 4.4 mi/hr. Assume that speeds follow a normal distribution. What statistical test should be used to test the claim? (pick one of the options) 1. t-test 2. 2.73 3. 15 4. 10.9 5. 14 6. z-test 7. 2.52 8. 2.64 Calculate the value of standardized test statistic. (pick one of the options) 1. t-test 2. 2.73 3. 15 4. 10.9 5. 14 6. z-test 7. 2.52 8. 2.64 What is the degree of the freedom for the distribution of the test statistics. (pick one of the options) 1. t-test 2. 2.73 3. 15 4. 10.9 5. 14 6. z-test 7. 2.52 8. 2.64
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Options (Select)A.) negatively skewed, bimodal, normal, positively skewed, approximately normal please answer correctly. i'll like if its correct
1) Asshme that adults have IQ scores that are normally distributed with a mean of 103.1 and a standard deviation 15.6. Find the first quartile Q1, which is the IQ score separating the bottom 25% from the top 75%.(Draw a graph) The first quartile is______(round one decimal as needed) 2)Assume that adults have IQ scores that are normally distributed with a mean of 99.2 and a standard deviation of 21.9. Find the probability that a randomly selected adult has an IQ greater than 136.3.(Draw a graph) The probability that a randomly selected adult from this group has an IQ greater than 136.3 is_____(Round to 4 decimal places as needed)