PROCEDURE 1000 mg L-asocrbic acid tablet (pulverized into fine powder)Molar mass of tablet = 176.12 g/mol1. Add the necessary amount of distilled water to make the desired concentration of stock solution. [Note: Assume that the volume of the solute is negligible compared to the volume of the solution.]Concentration of STOCK SOLUTION, MConcentration of DILUTED SOLUTION, M0.8 M0.16 M2. Mix and stir the powder with the distilled water until homogeneous.3. Get ready for the dilution. Refer to the table above.4. Compute and add more solvent to achieve the desired dilution. Use the prepared stock solution to prepare an aliquot assigned to your group. Make sure to place the computations used for dilution (C1V1 = C2V2) in the data sheet. 5. After dilution, label the aliquot with its concentration and total volume of solution.6. Complete the data sheet with relevant solutions in solving for the amounts needed in the experiment.PLEASE FILL IN THE MISSING TABLES IN THE DATA SHEET. THANK YOU! C. Dilution of Stock SolutionConcentration of STOCK solution you prepared (M)0.8Volume of STOCK solution you prepared (mL)Volume of STOCK solution used for dilution (mL)Assigned concentration for the DILUTED solution (M)0.16Volume of DILUTED solution prepared (mL)Volume of water ADDED with the STOCK solution(mL)Computations involved(You may opt to handwrite, OR you may handwrite, then scanthe computations in the space below. Ensure of legible and readable output) B. Preparation of Stock SolutionComputations involved(You may opt to handwrite, OR you may handwrite, then scanthe computations in the space below. Ensure of legible and readable output)Mass of active ingredient of the ascorbic acid tablet = 1000 mgAmount of solute used = 1000 mg = 1.0 gAssigned concentration of stock solution = 0.8 MWsolute(g)1*М-MWsolute (g/mol)V(L)1.0 g10.8 mol/L176.12 g/molV1.0 gV =0.8 mol/L * 176.12 g/mol= 7.1 * 10-3 L= 7.1 mL7.1 mL of water solvent should be added to 1000 mg 'solute’ to get 0.8 M stock solution ofascorbic acid.

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Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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PROCEDURE

1000 mg L-asocrbic acid tablet (pulverized into fine powder)

Molar mass of tablet = 176.12 g/mol

1. Add the necessary amount of distilled water to make the desired concentration of stock solution. [Note: Assume that the volume of the solute is negligible compared to the volume of the solution.]

Concentration of STOCK SOLUTION, M	Concentration of DILUTED SOLUTION, M
0.8 M	0.16 M

2. Mix and stir the powder with the distilled water until homogeneous.

3. Get ready for the dilution. Refer to the table above.

4. Compute and add more solvent to achieve the desired dilution. Use the prepared stock solution to prepare an aliquot assigned to your group. Make sure to place the computations used for dilution (C1V1 = C2V2) in the data sheet.

5. After dilution, label the aliquot with its concentration and total volume of solution.

6. Complete the data sheet with relevant solutions in solving for the amounts needed in the experiment.

PLEASE FILL IN THE MISSING TABLES IN THE DATA SHEET. THANK YOU!

C. Dilution of Stock Solution
Concentration of STOCK solution you prepared (M)
0.8
Volume of STOCK solution you prepared (mL)
Volume of STOCK solution used for dilution (mL)
Assigned concentration for the DILUTED solution (M)
0.16
Volume of DILUTED solution prepared (mL)
Volume of water ADDED with the STOCK solution(mL)
Computations involved
(You may opt to handwrite, OR you may handwrite, then scan
the computations in the space below. Ensure of legible and readable output)

B. Preparation of Stock Solution
Computations involved
(You may opt to handwrite, OR you may handwrite, then scan
the computations in the space below. Ensure of legible and readable output)
Mass of active ingredient of the ascorbic acid tablet = 1000 mg
Amount of solute used = 1000 mg = 1.0 g
Assigned concentration of stock solution = 0.8 M
Wsolute(g)
1
*
М-
MWsolute (g/mol)
V(L)
1.0 g
1
0.8 mol/L
176.12 g/mol
V
1.0 g
V =
0.8 mol/L * 176.12 g/mol
= 7.1 * 10-3 L
= 7.1 mL
7.1 mL of water solvent should be added to 1000 mg 'solute’ to get 0.8 M stock solution of
ascorbic acid.

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