having In the ng point of sofution is lower than the true. This means The ATE Will we high and the molar mass OF Solute would be low. x .02=1.168 freezing point read incorrectly; that that 6. What mass of NaCl is dissolved in 200 g of water in a 0.100 m solution? 758.44g 200g. Ihg 1000g (mol (.aig)(.100) mol = .02 = 0.akg mol = Nacl =1g. Mass of Mass = moles x Molar mass ng 7. Calculate the molalities of some commercial reagents from the following data: HCl(aq) NH3(aq) 17.03 Formula weight (g/mol) Density of solution (g/mL) Weight % Molarity 36.465 1.19 0.90 37.2 28.0 12.1 14.8 m= mol ng sof vent 8. A solution containing 1.00 g of an unknown nonelectrolyte liquid and 9.00 g water has a freezing point of -3.33 °C. The Kf= 1.86 °C/m for water. Calculate the molar mass of the unknown liquid in g/mol.

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Can you please explain #7 I really do get confuse when they say to look for m and I don't know what to use 

6. What mass of NaCl is dissolved in 200 g of water in a 0.100 m solution?
the free2ing point of solution is lower than the true. This means that
The ATF will we high and the molar mass Of solute would be loww.
would the calculated molar mass of the solute have been too high or too low? Bxplam
In having
the
T reezrng point of solution is lowerr than the tue. This means tha
he Ale wl we high and the mofan ma ss of solute would be Tow.
Freezing Point read incorrectly; that means that the
6. What mass of NaCl is dissolved in 200 g of water in a 0.100 m solution?
%3D
258.449 x .02=1.1698
う58.44g
200g. Thg = 0.akg
0.akg mol = (aa)(.100)
1000g
mol
Mass of Nacl= 19
mol = o02
%3D
Mass = moles × Molar mass
%3D
1. Calculate the molalities of some commercial reagents from the following data:
HCl(aq)
36.465
NH3(aq)
17.03
Formula weight (g/mol)
Density of solution (g/mL)
Weight %
Molarity
1.19
0.90
37.2
28.0
12.1
14.8
M= mol
Kg sofvent
8. A solution containing 1.00 g of an unknown nonelectrolyte liquid and 9.00 g water has a freezing point of
-3.33 °C. The Kf= 1.86 °C/m for water. Calculate the molar mass of the unknown liquid in g/mol.
Transcribed Image Text:6. What mass of NaCl is dissolved in 200 g of water in a 0.100 m solution? the free2ing point of solution is lower than the true. This means that The ATF will we high and the molar mass Of solute would be loww. would the calculated molar mass of the solute have been too high or too low? Bxplam In having the T reezrng point of solution is lowerr than the tue. This means tha he Ale wl we high and the mofan ma ss of solute would be Tow. Freezing Point read incorrectly; that means that the 6. What mass of NaCl is dissolved in 200 g of water in a 0.100 m solution? %3D 258.449 x .02=1.1698 う58.44g 200g. Thg = 0.akg 0.akg mol = (aa)(.100) 1000g mol Mass of Nacl= 19 mol = o02 %3D Mass = moles × Molar mass %3D 1. Calculate the molalities of some commercial reagents from the following data: HCl(aq) 36.465 NH3(aq) 17.03 Formula weight (g/mol) Density of solution (g/mL) Weight % Molarity 1.19 0.90 37.2 28.0 12.1 14.8 M= mol Kg sofvent 8. A solution containing 1.00 g of an unknown nonelectrolyte liquid and 9.00 g water has a freezing point of -3.33 °C. The Kf= 1.86 °C/m for water. Calculate the molar mass of the unknown liquid in g/mol.
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