3. Calculate AH for the reaction 4 NO(g) + 6 H2O (g) -4 NH (g) + 5 O: (g), from the following data N: (g) + O2(g) 2 NO (g) AH--180.5 kJ N: (g) + 3 H2(g)-2 NH: (g) AH-91.8 kJ 2 H: (g) + O2(g) → 2 H2O (g) AH--483.6 kJ
3. Calculate AH for the reaction 4 NO(g) + 6 H2O (g) -4 NH (g) + 5 O: (g), from the following data N: (g) + O2(g) 2 NO (g) AH--180.5 kJ N: (g) + 3 H2(g)-2 NH: (g) AH-91.8 kJ 2 H: (g) + O2(g) → 2 H2O (g) AH--483.6 kJ
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Problem Set 5 - Chapter 5
3. Calculate ΔH for the reaction 4 NO (g) + 6 H₂O (g) → 4 NH₃ (g) + 5 O₂ (g), from the following data.
- N₂ (g) + O₂ (g) → 2 NO (g) ΔH = -180.5 kJ
- N₂ (g) + 3 H₂ (g) → 2 NH₃ (g) ΔH = -91.8 kJ
- 2 H₂ (g) + O₂ (g) → 2 H₂O (g) ΔH = -483.6 kJ
4. Calculate ΔH for the reaction 2 Al (s) + 3 Cl₂ (g) → 2 AlCl₃ (s), given:
- 2 Al (s) + 6 HCl (aq) → 2 AlCl₃ (aq) + 3 H₂ (g) ΔH = -1049 kJ
- HCl (g) → HCl (aq) ΔH = -74.8 kJ
- H₂ (g) + Cl₂ (g) → 2 HCl (g) ΔH = -184.5 kJ
- AlCl₃ (s) → AlCl₃ (aq) ΔH = -323 kJ
(Note: The text provided above is a transcription intended for educational purposes and assumes familiarity with chemical reactions and thermodynamics concepts.)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd7374a00-925b-4659-a7ff-f60a4e3f7577%2Fc66cc18b-ad4c-4974-b657-c7bf31fecf6f%2Faefe2ee_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Problem Set 5 - Chapter 5
3. Calculate ΔH for the reaction 4 NO (g) + 6 H₂O (g) → 4 NH₃ (g) + 5 O₂ (g), from the following data.
- N₂ (g) + O₂ (g) → 2 NO (g) ΔH = -180.5 kJ
- N₂ (g) + 3 H₂ (g) → 2 NH₃ (g) ΔH = -91.8 kJ
- 2 H₂ (g) + O₂ (g) → 2 H₂O (g) ΔH = -483.6 kJ
4. Calculate ΔH for the reaction 2 Al (s) + 3 Cl₂ (g) → 2 AlCl₃ (s), given:
- 2 Al (s) + 6 HCl (aq) → 2 AlCl₃ (aq) + 3 H₂ (g) ΔH = -1049 kJ
- HCl (g) → HCl (aq) ΔH = -74.8 kJ
- H₂ (g) + Cl₂ (g) → 2 HCl (g) ΔH = -184.5 kJ
- AlCl₃ (s) → AlCl₃ (aq) ΔH = -323 kJ
(Note: The text provided above is a transcription intended for educational purposes and assumes familiarity with chemical reactions and thermodynamics concepts.)
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