Problem No.6 The following data are the observed elevation of a point running a line of levels over 6 different routes. Determine a) Relative weight of each route. b) Most Probable Value of the Elevation. Route 1 2 3 4 5 6 Observed Elevation 340.22 340.30 340.26 340.24 340.32 340.25 o Probable Error ±0.011 ±0.008 +0.018 +0.012 +0.0085 ±0.013

Problem No.6 The following data are the observed elevation of a point running a line of levels over 6 different routes. Determine a) Relative weight of each route. b) Most Probable Value of the Elevation. Route 1 2 3 4 5 6 Observed Elevation 340.22 340.30 340.26 340.24 340.32 340.25 o Probable Error ±0.011 ±0.008 +0.018 +0.012 +0.0085 ±0.013

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Q.3 A level circuit is shown in figure. The survey, needed for local engineering project, commenced at BM 35, the elevation of new benchmarks 36, 37, 38 and 39 were determined, and then the level survey was looped back to BM 35, the point of commencement. Fined the adjusted new BMs. ВМ 35 Elevation(m) 185.000(fixed) 35 36 37 38 39 35 184.242 187.299 186.251 188.397 184.933 BM 36 0.9 km. вм 35 0.8 km OBM 37 0.8 km 0.6 km BM 39 BM 38 0.7 km
Q.3 A level circuit is shown in figure. The survey, needed for local engineering project, commenced at BM 35, the elevation of new benchmarks 36, 37, 38 and 39 were determined, and then the level survey was looped back to BM 35, the point of commencement. Fined the adjusted new BMs. ВМ 35 Elevation(m) 190.000(fixed) 35 36 37 38 39 35 188.242 186.299 188.251 186.397 190.033 IM 36 09 km DM 35 0.8 km OBM 37 08 km O6 km DM 39 BM 30 0.7 km
46 K/s ۱۸ من ۱۸ Q.3 A level circuit is shown in figure. The survey, needed for local engineering project, commenced at BM 35, the elevation of new benchmarks 36, 37, 38 and 39 were determined, and then the level survey was looped back to BM 35, the point of commencement. Fined the adjusted new BMs. ВМ 35 Elevation(m) 119.010(fixed) 35 36 37 38 39 35 123.342 118.206 118.451 120.491 118.933 BM 38 0.9 kg BM 35 DUM 37 08 km 06 km BM 38 سلوان 2 8:11p äc lul 21.03.06
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Q.3 A level circuit is shown in figure. The survey, needed for local engineering project, commenced at BM 35, the elevation of new benchmarks 36, 37, 38 and 39 were determined, and then the level survey was looped back to BM 35, the point of commencement. Fined the adjusted new BMs. ВМ 35 35 36 37 38 39 35 Elevation(m) | 185.000(fixed) 184.242 187.299 186.251 188.397 184.933 BM 36 0.9 km вм 35 0.8 km Фвм 37 0.8 km 0.6 km BM 39 вм 38 0.7 km
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12. PROBABLE ERROR. A surveying instructor sent all the 10 students in his class out to measure a distance between wo points marked on a runway. The students working in of groups tollows: 920.45, 921.05, 921.65, 920.25, 92o.15, 921.85, 921.95, 920.45, values are equally reliable and that variations result oaly trom accidental errors, determine the relative precision of four came up with 10 different measurements as 921.15, and 921.35 me ters. Assuming these a single measurement and the relative precision of the mean.
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Two triangulation towers 120 m apart are on the samehorizontal plane. A surveyor standing and setting upsuccessively the transit at the bases of the towersobserves that the angle of elevation of the taller is twicethat of smaller. At the midway point, he observes that theangles of elevation are complementary angles. The heightof the instruments in all set up are is maintained to be 1.20m from the plane. Determine the height of the smallertower.
3. Given the following three wire leveling notes: Station Backsight Stadia BM1 Foresight Stadia Elevation 425.00 1.152 1.117 0.935 0.899 0.718 0.662 TP1 2.784 1.904 2.420 1.537 2.057 1.172 ТР2 2.591 2.210 2.094 1.714 1.599 1.218 BM2 a. Find the difference in elevation of TP2 and BM1, b. Find the elevation of BM2
complete the different leveling notes by providing data to the unknown quantities. show solution
C. Table: Determination of Stadia Interval Factor (K) D. TRIAL 1 2 3 4 5 6 7 8 DISTANCE STADIA HAIR READINGS UPPER LOWER 15.00 20.00 25.00 30.00 35.00 40.00 45.00 50.00 Where: SKETCH: 1.319 m 1.335 1.358 1.367 1.415 1.435 1.460 1.445 1.169 m 1.135 1.108 1.065 1.035 1.035 1.010 0.935 S = Stadia Intercept K = Stadia Interval Factor STADIA STADIA INTERCEPT INTERVAL FACTOR (K) COMPUTATIONS: 1. Computing Stadia Intercept (S) and Stadia Interval Factor (K). a.) Stadia Intercept = Upper Rod Reading - Lower Rod Reading b.) Stadia Interval Factor (K) = Distance / Stadia Intercept (S) AVERAGE K = (Show computations on the computed stadia intercept and stadia interval factor.) (Draw the resulting figure based on the data given data. Refer to the illustration above.)