Problem No. 1 A symmetrical parabolic curve connects two grades of 6% and -4%. It is to pass through a point "P"on the curve at station 25 +140 having an elevation of 98.34. If the elevation of the grade of intersection is 100m with a stationing of 25+ 160. Calculate thefollowing A Itthe curve a sag or a summit? B Length the curve C Stationing of the highest/lowest point on the curve.

Traffic and Highway Engineering
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ISBN:9781305156241
Author:Garber, Nicholas J.
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Chapter15: Geometric Design Of Highway Facilities
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Hi! can someone help me answer these 3 problems, please. Thank you!

Problem No. 1
A symmetrical parabolic curve connects two grades of 6% and -4%. It is to pass
through a point "P"on the curve at station 25 + 140 having an elevation of 98.34. If the
elevation of the grade of intersection is 100m with a stationing of 25 + 160. Calculate
thefollowing
A. Itthe curve a sag or a summit?
B. Length the curve
C. Stationing of the highest/lowest point on the curve.
D. Eleavtion of station 25+ 120 on the curve.
PROBLEM NO. 2
A symmetrical parabolic curve passes through point A whose elevation is 23.23m at
a distance of 54m from the PC. The elevation of the PC at station 4 + 100 is 22.56.
The grade at the back tangent is +2% and length of the is 120 m. Compute the
following:
A. The grade of the forward tangent
B. Stationg and elevation of the highest point of the curve
Problem no. 3
A forward tangent having a slope of -4% intersects the back tangent having a
slope +7% at point V at stations 6 + 300 having an elevation of 230m. It is
required to connect the two tangents with an unsymmetrical parabolic curve
that shall pass through point A on the curve having the elevation of 227.57m at
station 6+ 270. The length of the curve on the side of the back tangent is 60m.
A. Determine the length of the curve on the side of the forward tangent.
B. Determine the stationing and elevation of the highest point on the
Curve.
Transcribed Image Text:Problem No. 1 A symmetrical parabolic curve connects two grades of 6% and -4%. It is to pass through a point "P"on the curve at station 25 + 140 having an elevation of 98.34. If the elevation of the grade of intersection is 100m with a stationing of 25 + 160. Calculate thefollowing A. Itthe curve a sag or a summit? B. Length the curve C. Stationing of the highest/lowest point on the curve. D. Eleavtion of station 25+ 120 on the curve. PROBLEM NO. 2 A symmetrical parabolic curve passes through point A whose elevation is 23.23m at a distance of 54m from the PC. The elevation of the PC at station 4 + 100 is 22.56. The grade at the back tangent is +2% and length of the is 120 m. Compute the following: A. The grade of the forward tangent B. Stationg and elevation of the highest point of the curve Problem no. 3 A forward tangent having a slope of -4% intersects the back tangent having a slope +7% at point V at stations 6 + 300 having an elevation of 230m. It is required to connect the two tangents with an unsymmetrical parabolic curve that shall pass through point A on the curve having the elevation of 227.57m at station 6+ 270. The length of the curve on the side of the back tangent is 60m. A. Determine the length of the curve on the side of the forward tangent. B. Determine the stationing and elevation of the highest point on the Curve.
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