Problem I. Steel bars and an aluminum bar support the rigid slab as a platform as shown below. A gap A = 0.26 mmexists between the aluminum bar and the slab. Neglecting the weight of the slaba (/degree celsius)11.6x10-623.1x106A (mm?)E (GPa)Steel barAluminum bar35020040070a) Which temperature increase AT is required to just close the spacing at the middle? (Note that thetemperature increase will subject all bars)b)What are the stresses in the steel bars and aluminum bar for AT =_ degree celsius 76 AT in C°in MPa?1000 mmSteelAluminumSteel

Answered: Image /qna-images/answer/383393fa-8b36-48d8-9e85-9293583bb0be.jpg

Problem I. Steel bars and an aluminum bar support the rigid slab as a platform as shown below. A gap A = 0.26 mm exists between the aluminum bar and the slab. Neglecting the weight of the slab A (mm?) 350 a (/degree celsius) 11.6x10-6 23.1x106 E (GPa) Steel bar Aluminum bar 200 400 70 a) Which temperature increase AT is required to just close the spacing at the middle? (Note that the temperature increase will subject all bars) b) What are the stresses in the steel bars and aluminum bar for AT =_ degree celsius 76 AT in C° in MPa? 1000 mm Steel Aluminum Steel

Problem I. Steel bars and an aluminum bar support the rigid slab as a platform as shown below. A gap A = 0.26 mm exists between the aluminum bar and the slab. Neglecting the weight of the slab A (mm?) 350 a (/degree celsius) 11.6x10-6 23.1x106 E (GPa) Steel bar Aluminum bar 200 400 70 a) Which temperature increase AT is required to just close the spacing at the middle? (Note that the temperature increase will subject all bars) b) What are the stresses in the steel bars and aluminum bar for AT =_ degree celsius 76 AT in C° in MPa? 1000 mm Steel Aluminum Steel

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Please show your solution clearly thank you
A steel rod Is stretched two rigid walls and carries a tensile load of 6000 N to 20°C. Coefficient of thermal expansion a = 11.7 x 10-5 /C and modulus of elastičity 200000 MPa. 7. Which of the following gives the minimum diameter of the rod if the allowable stress is not to exceed 140 MPa at -25°C. a. 15 mm C. 16 mm b. 17 mm d. 18 mm 8. Which of the following gives the total elongation of the steel rod if it has a length of 1.5m. a. 1.00 mm С. 1.02 mm b. 1.04 mm d. 1.06 mm 9. Which of the following gives the strain of the steel rod. a. 0.00067 b. 0.00071 C. 0.00069 d. 0.00073
A typical aluminum-alloy scuba diving tank is shown. The outside diameter of the tank is 200 mm and the wall thickness is 12 mm. If the air in the tank is pressurized to 14MPa, determine the maximum shear stress in the plane of the cylinder wall. 24.1 MPa 15.5 MPa 25.7 MPa 32.2 MPa 20.9 MPa
NOTE: The aluminum bar was subjected to a temperature drop of 25 °C.
plz, solve this question ,it is not graded question. Reg.no : 5395
12. Assume a uniformly load simply support beam with a rectangular cross section. The width of the beam is fixed by other design considerations. Determine the ratio between the difference in depth required for an aluminum beam compared to a steel beam in order to obtain the same maximum deflection. MOE aluminum can be taken as 10,000 ksi, for steel as 30,000 ksi. The maximum deflection for the beam is 5wl*/384EI Factoring the deflection equations we can conclude that for equal deflection Eala = Esls where subscripts a and s represent values for aluminum and steel. The depth of must be times the depth of the
X Your answer is incorrect. Two polymer bars are connected to a rigid plate at B, as shown. Bar (1) has a cross-sectional area of 1.42 in.? and an elastic modulus of 2180 ksi. Bar (2) has a cross-sectional area of 1.139 in.? and an elastic modulus of 4150 ksi. Assume L;-23 in., L2-41 in., Q-6.7 kips, P-3.7 kips, and R-14.1 kips. Determine the horizontal deflection of end Crelative to end A. R (1) (2) P L1 L2 Answer: UCIA - i 0.0725 in.
If the temperature increases by 95°F, calculate the increase in stress for the steel segment shown. Assume the supports are unyielding and the bar is braced against buckling. E (psi) 10x10 Area (in?) a (in/in°F) 12.8x10-4 Steel Aluminum 2 1.5 29 x10 6.5x10- Steel Aluminum 10 in 15 in
Determine principal stress
The figure below shows a 1.3-in.-diameter ball loaded in compression by a 2600 lb force against the left end of a bar where the cross section is 1.7 in. x 1.7 in. The balls are hardened steel and the steel bar has a yield strength of 45 ksi. What maximum contact stress will result from the load of F = 2600 lb? Submit your answer in ksi. F F. 10 16 18
thank you. Civil engineering - strength of materials
SHOW COMPLETE SOLUTION AND SKETCH THE ILLUSTRATION