;ProblemACT1726222421161819282622239GPA1.93.43.72.72.31.62.923.93.12.429.9X22896764845764412563243617846764845351Y23.6111.5613.697.295.292.568.41415.219.615.7686.99XY32.388.481.4 n=1164.848.325.652.238109.280.6What does it tell you about therelationship between the ACT score52.8 and GPA of these 11 students?673.6

The provided information is as follows:Here, is the ACT. is the GPA.67

Answered: Problem ACT 162 17 26 22 24 21 16 18…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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5. 6. 1 5 7 6 5 1 5 7 2 8 6 4 1 9 8 5 6 7 4 4 1 9 3 3 6 8
141% v Zoom Add Page Insert Table Chart Text Shape Media Comment Collaborate Format Document 13! 6227020800 14! 87178291200 This document has missing fonts. Show 15! 1307674368000 16! 20922789888000 17! 355687428096000 18! 6402373705728000 19! 121645100408832000 20! 2432902008176640000 2) After a recent bank robbery, three eyewitnesses reported seeing a man with glasses flee the scene. The police suspect Ricky and make up an identity parade of five men with glasses. Ricky takes his place in the parade alongside four randomly chosen stooges. Two of the eyewitnesses identify Ricky and the third points to one of the stooges. What's the probability that Ricky would have been chosen by two of the three eyewitnesses if each witness had chosen completely at random? Solve this problem using the Binomial Probability Mass Function. (Tip: This problem will be easier to solve if you first find p, the probability of success on any one trial; in other words, the probability of a single eyewitness…
The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the eighth grade level. Suppose a sample of 2552 tenth graders is drawn. Of the students sampled, 2119 read above the eighth grade level. Using the data, estimate the proportion of tenth graders reading at or below the eighth grade level. Enter your answer as a fraction or a decimal number rounded to three decimal places.
Number of ChildrenTable 1 shows the number of women (per 1000) between 15 and 50 years of age who have been married grouped by the number of children they have had. Table 2 gives the same information for women who have never been married.1 Number of Children Women per 1000 0 162 1 213 2 344 3 182 4 69 5+ 32 Table 1 Women who have been married Number of Children Women per 1000 0 752 1 117 2 72 3 35 4 15 5+ 10 Table 2 Women who have never been married 1http://www.census.gov/hhes/fertility/data/cps/2014.html, Table 1, June 2014. Condition gt requires numbers instead of "null" and "0" (a) Without doing any calculations, which of the two samples appears to have the highest mean number of children? Women who have been marriedWomen who have never been married Which of the distributions appears to have the mean most different from the median? Women who have been marriedWomen who have never been married…
3) If no one had smoked, how many deaths from lung cancer would have been averted?
12 11 12 10 12 11 12 11 10 10 10 1:11 12 11 12 11 12 11 12 11 10 10 10 10 6. 12 11 12 11 12 11 12 11 10 10 10 10 12. 1. 12 11 12 11 11 10 10 10 10 RI 8. 91 91 3. 1.
Sex (1=Male 2=Female) 1 2 Total Ever told heart disease (1=Yes 2=No) 1 Count 73 96 169 % within Ever told heart 43.2% 56.8% 100.0% disease (1=Yes 2=No) % within Sex (1=Male 10.2% 9.3% 9.7% 2=Female) % of Total 4.2% 5.5% 9.7% 2 Count 640 941 1581 % within Ever told heart 40.5% 59.5% 100.0% disease (1=Yes 2=No) % within Sex (1=Male 89.8% 90.7% 90.3% 2=Female) % of Total 36.6% 53.8% 90.3% Total Count 713 1037 1750 % within Ever told heart disease (1=Yes 2=No) 40.7% 59.3% 100.0% % within Sex (1=Male 100.0% 100.0% 100.0% 2=Female) % of Total 40.7% 59.3% 100.0% What percent of the sample is male and has heart disease? 4.2% 40.5% 43.2% 10.2%
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