Problem: A pump draws water through a 300-mm diameter cast iron pipe, 15 m long from a reservoir in which the water surface is 4.5 m higher than the pump and discharges through a 250-mm diameter cast iron, 75 m long, to an elevated tank in which the water surface is 60 m higher than the pump. Considering f = 0.02 and the coefficients for minor head losses (kentrance = 0.5, kpend = 0.35, and kexit = 0.5), compute the following: a. Pressure head at the suction side of the pump b. Pressure head at the discharge side of the pump c. Horsepower output of the pump Note: generally, total minor head losses =E h,m, ; hm, = kentrance hm, = kpend hm, = kexit Elev.B T

Elements Of Electromagnetics
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Problem: A pump draws water through a 300-mm diameter cast iron pipe, 15 m long from a reservoir
in which the water surface is 4.5 m higher than the pump and discharges through a 250-mm diameter
cast iron, 75 m long, to an elevated tank in which the water surface is 60 m higher than the pump.
Considering f = 0.02 and the coefficients for minor head losses (kentrance = 0.5,
kpend = 0.35, and kexit = 0.5), compute the following:
a. Pressure head at the suction side of the pump
b. Pressure head at the discharge side of the pump
c. Horsepower output of the pump
Note: generally, total minor head losses =E h,m, ; hm, = kentrance
; hm, = kpend :
2g
hm, = kexit
2g
29
Elev.B
kexit
60 m
250 тm Ф
300 тm Ф
Elev. A
kpend
kentrance
Transcribed Image Text:Problem: A pump draws water through a 300-mm diameter cast iron pipe, 15 m long from a reservoir in which the water surface is 4.5 m higher than the pump and discharges through a 250-mm diameter cast iron, 75 m long, to an elevated tank in which the water surface is 60 m higher than the pump. Considering f = 0.02 and the coefficients for minor head losses (kentrance = 0.5, kpend = 0.35, and kexit = 0.5), compute the following: a. Pressure head at the suction side of the pump b. Pressure head at the discharge side of the pump c. Horsepower output of the pump Note: generally, total minor head losses =E h,m, ; hm, = kentrance ; hm, = kpend : 2g hm, = kexit 2g 29 Elev.B kexit 60 m 250 тm Ф 300 тm Ф Elev. A kpend kentrance
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