Problem 9: A guitar with strings of length L = 0.64 m has new strings put on it. The low E string has a linear density of p = 0.0051 kg/m and when tuned properly should produce a fundamental tone of v = 82.41 Hz.

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Chapter1: Units, Trigonometry. And Vectors
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Problem 9: A guitar with strings of length L = 0.64 m has new strings put on it. The low E string has a linear
density of p = 0.0051 kg/m and when tuned properly should produce a fundamental tone of v = 82.41 Hz.
Randomized Variables
L = 0.64 m
p = 0.0051 kg/m
Part (a) What is the proper tension the string should be under, in Newtons?
Numeric : Anumeric value is expected and not an expression.
T =
Part (b) If the string was mistakenly tuned to high E (v = 330 Hz) what would the tension be, in Newtons? (Note that in
reality, the string would likely break!)
Numeric : A numeric value is expected and not an expression.
T =
Transcribed Image Text:Problem 9: A guitar with strings of length L = 0.64 m has new strings put on it. The low E string has a linear density of p = 0.0051 kg/m and when tuned properly should produce a fundamental tone of v = 82.41 Hz. Randomized Variables L = 0.64 m p = 0.0051 kg/m Part (a) What is the proper tension the string should be under, in Newtons? Numeric : Anumeric value is expected and not an expression. T = Part (b) If the string was mistakenly tuned to high E (v = 330 Hz) what would the tension be, in Newtons? (Note that in reality, the string would likely break!) Numeric : A numeric value is expected and not an expression. T =
Expert Solution
Formula used.

Wavelength of wave in string

λ =2L

frequency is given as

f = Tμλ = 12LTμ

T = 2fL2μ

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