In Figure (a), string 1 has a linear density of 2.14 g/m, and string 2 has a linear density of 7.16 g/m. They are under tension due to the hanging block of mass M = 490 g. Calculate the wave speed on (a) string 1 and (b) string 2. (Hint: When a string loops halfway around a pulley, it pulls on the pulley with a net force that is twice the tension in the string.) Next the block is divided into two blocks (with M1 + M2 = M) and the apparatus is rearranged as shown in Figure (b). Find (c)  M1 and (d)  M2 such that the wave speeds

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Chapter1: Units, Trigonometry. And Vectors
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In Figure (a), string 1 has a linear density of 2.14 g/m, and string 2 has a linear density of 7.16 g/m. They are under tension due to the hanging block of mass M = 490 g. Calculate the wave speed on (a) string 1 and (b) string 2. (Hint: When a string loops halfway around a pulley, it pulls on the pulley with a net force that is twice the tension in the string.) Next the block is divided into two blocks (with M1 + M2 = M) and the apparatus is rearranged as shown in Figure (b). Find (c)  M1 and (d)  M2 such that the wave speeds in the two strings are equal.

- Sring 1
String 2-
- Knot
M
(a)
-String 1
String 2
| M2
(b)
Transcribed Image Text:- Sring 1 String 2- - Knot M (a) -String 1 String 2 | M2 (b)
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