Problem 78 IR Spectrum (liquid film) 800 1600 2000 V (cm1) 4000 3000 1200 100 Mass Spectrum UV Spectrum 105 80 A max = 260 nm (log,0ɛ=2.5) 60 40 M+'= 134 20 40 80 120 160 200 240 280 m/e 13C NMR Spectrum (100.0 MHz, CDCI, solution) solvent proton decoupled 200 160 120 80 40 8 (ppm) 1H NMR Spectrum expansion (400 MHz, CDCI, solution) expansions expansion 7.3 ppm 2.8 2.7 ppm 1.8 1.7 ppm 1.45 1.35 ppm 1.05 0.95 7.5 TMS 1 8 (ppm) 10 9. 8 7 4 3 2 % of base peak
Problem 78 IR Spectrum (liquid film) 800 1600 2000 V (cm1) 4000 3000 1200 100 Mass Spectrum UV Spectrum 105 80 A max = 260 nm (log,0ɛ=2.5) 60 40 M+'= 134 20 40 80 120 160 200 240 280 m/e 13C NMR Spectrum (100.0 MHz, CDCI, solution) solvent proton decoupled 200 160 120 80 40 8 (ppm) 1H NMR Spectrum expansion (400 MHz, CDCI, solution) expansions expansion 7.3 ppm 2.8 2.7 ppm 1.8 1.7 ppm 1.45 1.35 ppm 1.05 0.95 7.5 TMS 1 8 (ppm) 10 9. 8 7 4 3 2 % of base peak
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:Problem 78
IR Spectrum
(liquid film)
4000
3000
2000
1600
1200
800
v (cm1)
100
Mass Spectrum
UV Spectrum
105
80
A max 260 nm (log10ɛ2.5)
60
40
M+:= 134
20
40
80
120
160
200
240
280
m/e
13C NMR Spectrum
(100.0 MHz, CDCI, solution)
solvent
proton decoupled
200
160
120
80
40
8 (ppm)
1H NMR Spectrum
expansion
(400 MHz, CDCI, solution)
expansions
expansion
7.5
7.3 ppm
2.8
2.7 ppm
1.8
1.7 ppm
1.45 1.35 ppm
1.05
0.95
TMS
1
d (ppm)
10
9.
8.
7
5
4
3
2
% of base peak
LO
Transcribed Image Text:Unknown Spectroscopy Practice Problems: Problem #78
Molecular formula & DU:
Proposed structure and 'H NMR assignment:
H NMR Boetram
, Coo, o
il
1 7 en
148 13 R
TMS
10
4
8 (ppm)
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