Problem 5. (30pts) An aqueduct with a rectangular flow area has a depth, y=10ft, and a width, b=30ft. A sketch of the side profile of a reach of the aqueduct is shown below. To note, y is the depth of the channel, while z is the coordinate system. The velocity profile has been approximated by the equation shown below, where Vmax is 10ft/s. Assume that the velocity profile is constant across the width of the channel. Approximate the shear stress at midpoint and top of the channel given that the viscosity of the water is 3.5x10-51bf-s/ft². What would happen if we tried to approximate shear stress at the bottom, given the velocity profile equation? V(z)= Vmax Z *
Problem 5. (30pts) An aqueduct with a rectangular flow area has a depth, y=10ft, and a width, b=30ft. A sketch of the side profile of a reach of the aqueduct is shown below. To note, y is the depth of the channel, while z is the coordinate system. The velocity profile has been approximated by the equation shown below, where Vmax is 10ft/s. Assume that the velocity profile is constant across the width of the channel. Approximate the shear stress at midpoint and top of the channel given that the viscosity of the water is 3.5x10-51bf-s/ft². What would happen if we tried to approximate shear stress at the bottom, given the velocity profile equation? V(z)= Vmax Z *
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:Problem 5. (30pts) An aqueduct with a rectangular flow area has a depth, y=10ft, and a width, b=30ft.
A sketch of the side profile of a reach of the aqueduct is shown below. To note, y is the depth of the
channel, while z is the coordinate system. The velocity profile has been approximated by the equation
shown below, where Vmax is 10ft/s. Assume that the velocity profile is constant across the width of the
channel. Approximate the shear stress at midpoint and top of the channel given that the viscosity of the
water is 3.5x10-51bf-s/ft². What would happen if we tried to approximate shear stress at the bottom, given
the velocity profile equation?
V(z)= Vmax
Z
*
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