Problem 5: Suppose you are told that a satellite orbiting the Earth has a orbital period of 0.85 hours. a)Using the orbital characteristics of the Moon (RM = 3.84 × 105km and TM = 0.0748 y), use Kepler's laws to calculate the orbital radius for the satellite, in kilometers. b)What is unreasonable about this result?MultipleChoice :1) This radius is unreasonable because it is smaller than the orbital radius of the Moon.2) There is nothing unreasonable about the result.3) This radius is unreasonable because it is greater than the radius of the Earth.4) This radius is unreasonable because it is greater than the orbital radius of the Moon.5) This radius is unreasonable because it is smaller than the radius of Earth.
Problem 5: Suppose you are told that a satellite orbiting the Earth has a orbital period of 0.85 hours.
a)Using the orbital characteristics of the Moon (RM = 3.84 × 105km and TM = 0.0748 y), use Kepler's laws to calculate the orbital radius for the satellite, in kilometers.
b)What is unreasonable about this result?
MultipleChoice :
1) This radius is unreasonable because it is smaller than the orbital radius of the Moon.
2) There is nothing unreasonable about the result.
3) This radius is unreasonable because it is greater than the radius of the Earth.
4) This radius is unreasonable because it is greater than the orbital radius of the Moon.
5) This radius is unreasonable because it is smaller than the radius of Earth.
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