Problem 4b. For a free particle H = show that if 2m qpt, P=p then {Q, P} is an integral of motion (constant of motion).
Problem 4b. For a free particle H = show that if 2m qpt, P=p then {Q, P} is an integral of motion (constant of motion).
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![Problem 4b. For a free particle H = show that if
2m
1
Q= mq² – qpt, P= p
then {Q, P} is an integral of motion (constant of motion).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe0e76253-b524-48cf-bddd-98b2902cb6f2%2F78b23ecd-3626-4f20-b97a-606f7b1495a4%2Fg2pxvi_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Problem 4b. For a free particle H = show that if
2m
1
Q= mq² – qpt, P= p
then {Q, P} is an integral of motion (constant of motion).
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