Can you explain part b? Problem 4.181 The vector sum of the forces acting onthe beam is zero, and the sum of the moments about Ais zero.(a) What are the forces Ax, Ay, and B?(b) What is the sum of the moments about B?220 mm-260 mmEF₁₂ = A x + 400 co₂ 30° = 0 → Ax=-346NEMA = B(500) - 400 c0230° (220)=0 → B = 152NZE Fy=400 sin 30° + B + Ay = 0 → Ay = 47.6NBEM²₂² =도M을ZA30°x400 N500 mmB- Ax (260) - Ay (500) – 400,030° (480) + 400 sia 30° (500) = 0-400 co50 (260)-500 (400 Sun 30%) + 4000-50% (220)

force Ax = -346 N, Ay = 47.6 N, B = 152 N, F = 400 N Find: Sum of moments about point B

Problem 4.181 The vector sum of the forces acting on the beam is zero, and the sum of the moments about A is zero. (a) What are the forces Ax, Ay, and B? (b) What is the sum of the moments about B? { fy= Fy 220 mm EF₁x = Ax + 400 cos 30º =0 → A₂ = -346 N = M ₁/² = B(500) - 400 c0₂30° (220) = 0 → B = 152N ~ 400 sin 30° + B +Ay = 0 → Ay = 47.6 N B EM₂²³ = Z 260 mm O A A 30° 400 N 500 mm • Ax (260) - Ay (500) - 40000 30° (480) + 400 sim 30° (200) 400 50% (260)-500 (400 sun 30%) + 400 000 50 % (220) B = 0

Problem 4.181 The vector sum of the forces acting on the beam is zero, and the sum of the moments about A is zero. (a) What are the forces Ax, Ay, and B? (b) What is the sum of the moments about B? { fy= Fy 220 mm EF₁x = Ax + 400 cos 30º =0 → A₂ = -346 N = M ₁/² = B(500) - 400 c0₂30° (220) = 0 → B = 152N ~ 400 sin 30° + B +Ay = 0 → Ay = 47.6 N B EM₂²³ = Z 260 mm O A A 30° 400 N 500 mm • Ax (260) - Ay (500) - 40000 30° (480) + 400 sim 30° (200) 400 50% (260)-500 (400 sun 30%) + 400 000 50 % (220) B = 0

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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