Problem 4.181 The vector sum of the forces acting on the beam is zero, and the sum of the moments about A is zero. (a) What are the forces Ax, Ay, and B? (b) What is the sum of the moments about B? { fy= Fy 220 mm EF₁x = Ax + 400 cos 30º =0 → A₂ = -346 N = M ₁/² = B(500) - 400 c0₂30° (220) = 0 → B = 152N ~ 400 sin 30° + B +Ay = 0 → Ay = 47.6 N B EM₂²³ = Z 260 mm O A A 30° 400 N 500 mm • Ax (260) - Ay (500) - 40000 30° (480) + 400 sim 30° (200) 400 50% (260)-500 (400 sun 30%) + 400 000 50 % (220) B = 0

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Chapter1: Units, Trigonometry. And Vectors
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Can you explain part b?

Problem 4.181 The vector sum of the forces acting on
the beam is zero, and the sum of the moments about A
is zero.
(a) What are the forces Ax, Ay, and B?
(b) What is the sum of the moments about B?
220 mm
-
260 mm
EF₁₂ = A x + 400 co₂ 30° = 0 → Ax=-346N
EMA = B(500) - 400 c0230° (220)=0 → B = 152N
Z
E Fy=
400 sin 30° + B + Ay = 0 → Ay = 47.6N
B
EM²₂² =
도M을
Z
A
30°
x
400 N
500 mm
B
- Ax (260) - Ay (500) – 400,030° (480) + 400 sia 30° (500) = 0
-
400 co50 (260)-500 (400 Sun 30%) + 4000-50% (220)
Transcribed Image Text:Problem 4.181 The vector sum of the forces acting on the beam is zero, and the sum of the moments about A is zero. (a) What are the forces Ax, Ay, and B? (b) What is the sum of the moments about B? 220 mm - 260 mm EF₁₂ = A x + 400 co₂ 30° = 0 → Ax=-346N EMA = B(500) - 400 c0230° (220)=0 → B = 152N Z E Fy= 400 sin 30° + B + Ay = 0 → Ay = 47.6N B EM²₂² = 도M을 Z A 30° x 400 N 500 mm B - Ax (260) - Ay (500) – 400,030° (480) + 400 sia 30° (500) = 0 - 400 co50 (260)-500 (400 Sun 30%) + 4000-50% (220)
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